Bourbaki

Example 2

Tag 08H7, permanent. Cite it as [Bourbaki, Tag 08H7].

Functions of a Real Variable, chapter V, Appendix 0. Hardy Fields. (H) Functions

Let us seek an asymptotic expansion for the inverse function of the function x/log⁡xx / \log x; from the identity x=y/log⁡yx = y / \log y, where y=v(x)y = v(x), one deduces log⁡x=log⁡y−log⁡log⁡y\log x = \log y - \log \log y; on putting z=log⁡y,t=log⁡xz = \log y, t = \log x, one has t=z−log⁡zt = z - \log z, and one is led to expand the inverse function u(t)u(t) of t−log⁡tt - \log t; for example, one has

u2(t)=t+log⁡(t+log⁡t)=t+log⁡t+log⁡tt−(log⁡t)22t2+o1(log⁡tt2) u_2(t) = t + \log(t + \log t) = t + \log t + \frac{\log t}{t} - \frac{(\log t)^2}{2t^2} + o_1\left( \frac{\log t}{t^2} \right)
and moreover, by (11) (V, p. 256)
u(t)−u2(t)∼log⁡tt2 u(t) - u_2(t) \sim \frac{\log t}{t^2}
whence
u(t)=t+log⁡t+log⁡tt−(log⁡t)22t2+log⁡tt2+o2(log⁡tt2) u(t) = t + \log t + \frac{\log t}{t} - \frac{(\log t)^2}{2t^2} + \frac{\log t}{t^2} + o_2\left( \frac{\log t}{t^2} \right)
and on returning to the original problem one obtains the asymptotic expansion
v(x)=xlog⁡x+xlog⁡log⁡x+xlog⁡log⁡xlog⁡x+o(xlog⁡log⁡xlog⁡x). v(x) = x \log x + x \log \log x + x \frac{\log \log x}{\log x} + o\left( x \frac{\log \log x}{\log x} \right).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.