Bourbaki

Proposition 10

Tag 08LP, permanent. Cite it as [Bourbaki, Tag 08LP].

Integration, chapter III, § 1. Measures on a locally compact space

— For every measure μ\mu on XX,

(22)

∥μ∥=sup⁡0≤f≤1, f∈H(X;R)∣μ∣(f). \|\mu\| = \sup_{0 \leq f \leq 1,\ f \in \mathscr{H}(X; \mathbf{R})} |\mu|(f).

For, taking into account the formula (12) that defines the absolute value of a measure, the second member of (22) may be written

sup⁡0≤f≤1, f∈H(X;R)(sup⁡∣g∣≤f, g∈H(X;C)∣μ(g)∣)=sup⁡∥g∥≤1, g∈H(X;C)∣μ(g)∣. \sup_{0 \leq f \leq 1,\ f \in \mathscr{H}(X; \mathbf{R})} \left( \sup_{|g| \leq f,\ g \in \mathscr{H}(X; \mathbf{C})} |\mu(g)| \right) = \sup_{\|g\| \leq 1,\ g \in \mathscr{H}(X; \mathbf{C})} |\mu(g)|.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed volume. Not translated.