Bourbaki

Proposition 9

Tag 08OS, permanent. Cite it as [Bourbaki, Tag 08OS].

Integration, chapter III, § 4. Products of measures

Suppose that all of the measures μλ\mu_\lambda are positive and that the family (μλ(1))λ∈L(\mu_\lambda(1))_{\lambda \in L} is multipliable in R+\mathbf{R}_+ (with product possibly 0). Then there exists one and only one measure μ\mu on XX such that, for every finite subset JJ of LL and every function fJ∈C(XJ;C)f_J \in \mathscr{C}(X_J; \mathbf{C}),

μ(fJ∘prJ)=μJ(fJ)∏λ∈L−Jμλ(1). \mu(f_J \circ \mathrm{pr}_J) = \mu_J(f_J) \prod_{\lambda \in L - J} \mu_\lambda(1).

Moreover, the measure μ\mu is positive and its total mass is given by

μ(1)=∏λ∈Lμλ(1). \mu(1) = \prod_{\lambda \in L} \mu_\lambda(1).

Let FF be the vector space consisting of the functions on XX of the form fJ∘prJf_J \circ \mathrm{pr}_J, where JJ runs over the directed set of finite subsets of LL, and fJ∈C(XJ;C)f_J \in \mathscr{C}(X_J; \mathbf{C}); we again say that FF is the space of continuous functions on XX that depend only on a finite number of variables. Lemma 3 of No. 5 shows that FF is dense in C(X;C)\mathscr{C}(X; \mathbf{C}), which proves the uniqueness assertion. If μλ0=0\mu_{\lambda_0} = 0 for some λ0∈L\lambda_0 \in L then the measure μ=0\mu = 0 meets the requirements, since in the second member of (18) we have μJ(fJ)=0\mu_J(f_J) = 0 if λ0∈J\lambda_0 \in J and ∏λ∈L−Jμλ(1)=0\prod_{\lambda \in L - J} \mu_\lambda(1) = 0 if λ0∉J\lambda_0 \notin J. We can therefore suppose that μλ≠0\mu_\lambda \neq 0 for all λ∈J\lambda \in J and, since the measures μλ\mu_\lambda are positive, this implies that μλ(1)≠0\mu_\lambda(1) \neq 0 for all λ∈L\lambda \in L. Let us then set μλ′=μλ/μλ(1)\mu'_\lambda = \mu_\lambda / \mu_\lambda(1) for every λ∈L\lambda \in L, so that μλ′\mu'_\lambda is a positive measure on XλX_\lambda such that μλ′(1)=1\mu'_\lambda(1) = 1. It then follows from Prop. 8 of No. 5 that there exists a positive measure μ′\mu' on XX of total mass 1, such that μ′(fJ∘prJ)=μJ′(fJ)\mu'(f_J \circ \mathrm{pr}_J) = \mu'_J(f_J) for every finite subset JJ of LL and every function fJ∈C(XJ;C)f_J \in \mathscr{C}(X_J; \mathbf{C}). The positive measure

μ=(∏λ∈Lμλ(1))μ′ \mu = \left( \prod_{\lambda \in L} \mu_\lambda(1) \right) \mu'

then meets the requirements, since

μJ(fJ)=μJ′(fJ)⋅∏λ∈Jμλ(1), \mu_J(f_J) = \mu'_J(f_J) \cdot \prod_{\lambda \in J} \mu_\lambda(1),
∏λ∈Lμλ(1)=∏λ∈Jμλ(1)⋅∏λ∈L−Jμλ(1). \prod_{\lambda \in L} \mu_\lambda(1) = \prod_{\lambda \in J} \mu_\lambda(1) \cdot \prod_{\lambda \in L - J} \mu_\lambda(1).

The measure μ\mu defined in Prop. 9 is called the product measure of the family of positive measures (μλ)λ∈L(\mu_\lambda)_{\lambda \in L} and is denoted by ⨂λ∈Lμλ\bigotimes_{\lambda \in L} \mu_\lambda.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.