Bourbaki

Proposition 2

Tag 08YO, permanent. Cite it as [Bourbaki, Tag 08YO].

Integration, chapter IV, § 7. Barycenters

— Let K be a compact convex subset of a Hausdorff locally convex space E, μ\mu a positive measure of total mass 1 on K, bμb_\mu its barycenter. For every convex numerical function f≥0f \geq 0 that is lower semi-continuous on K,

f(bμ)≤∫∗fdμ. f(b_\mu) \leq \int^* f d\mu.
It is known (TVS, II, §5, No. 4, Prop. 5) that ff is the upper envelope of a family of restrictions to K of continuous affine linear functions hα:x↦cα+⟨x,zα′⟩h_\alpha : x \mapsto c_\alpha + \langle x, z'_\alpha \rangle. Then
∫hα(x)dμ(x)≤∫∗f(x)dμ(x) \int h_\alpha(x) d\mu(x) \leq \int^* f(x) d\mu(x)
for every α\alpha; now, ∫hα(x)dμ(x)=cα+∫⟨x,zα′⟩dμ(x)\int h_\alpha(x) d\mu(x) = c_\alpha + \int \langle x, z'_\alpha \rangle d\mu(x) since μ\mu has total mass 1; but ∫⟨x,zα′⟩dμ(x)=⟨bμ,zα′⟩\int \langle x, z'_\alpha \rangle d\mu(x) = \langle b_\mu, z'_\alpha \rangle by the definition of barycenter. Therefore sup⁡α∫hα(x)dμ(x)=sup⁡αhα(bμ)=f(bμ)\sup_\alpha \int h_\alpha(x) d\mu(x) = \sup_\alpha h_\alpha(b_\mu) = f(b_\mu), whence the conclusion.

When μ\mu is a discrete positive measure on K of total mass 1, Prop. 2 yields anew the inequality that defines the convex functions on K.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed volume. Not translated.