Bourbaki

Lemma 2

Tag 098Y, permanent. Cite it as [Bourbaki, Tag 098Y].

Integration, chapter VI, § 1. Integration of vector-valued functions

Let f be a mapping of T into Fs′F'_s, such that for every z∈Fz \in F, the numerical function ⟨z,f⟩\langle z, f \rangle belongs to L‾p(μ)\overline{\mathscr{L}}^p(\mu) (1≤p≤+∞1 \leq p \leq +\infty); let θ(z)\theta(z) be the class of this function in Lp(μ)L^p(\mu). Then z↦θ(z)z \mapsto \theta(z) is a continuous linear mapping of F into Lp(μ)L^p(\mu).

By virtue of the (GDF) property, it suffices to show that for every sequence (zn)(z_n) of elements of F converging to zz, such that (θ(zn))(\theta(z_n)) converges to u∈Lp(μ)u \in L^p(\mu), one has u=θ(z)u = \theta(z). Now, replacing if necessary the sequence (zn)(z_n) by a subsequence, one can suppose that the sequence of functions ⟨zn,f⟩\langle z_n, f \rangle converges locally almost everywhere to a function h∈L‾p(μ)h \in \overline{\mathscr{L}}^p(\mu), with class uu in Lp(μ)L^p(\mu) (Ch. IV, §3, No. 4, Th. 3 and Ch. V, §1, No. 3). Since, by hypothesis, for every t∈Tt \in T the sequence (⟨zn,f(t)⟩)(\langle z_n, f(t) \rangle) converges to ⟨z,f(t)⟩\langle z, f(t) \rangle, we have h(t)=⟨z,f(t)⟩h(t) = \langle z, f(t) \rangle locally almost everywhere, consequently u=θ(z)u = \theta(z).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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