Bourbaki

Remark

Tag 09B3, permanent. Cite it as [Bourbaki, Tag 09B3].

Integration, chapter VI, § 2. Vectorial measures . "

— When mm is of the form bμb\mu, where b∈Gb \in G and μ\mu is a real measure on TT,

IΦ,m(f)=∫Φ(f(t),b) dμ(t) I_{\Phi,m}(f) = \int \Phi(f(t), b)\,d\mu(t)

for every function f∈LF1(μ)f \in \mathscr{L}_F^1(\mu), because both members are continuous on this space and coincide when ff is a step function over the ∣μ∣|\mu|-integrable sets.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed volume. Not translated.