Bourbaki

Example

Tag 09E3, permanent. Cite it as [Bourbaki, Tag 09E3].

Integration, chapter VII, § 1. Construction of a Haar measure

— 1) Take K=RK = \mathbf{R}, A=CA = \mathbf{C}. Taking into account Alg., chap. VIII, §12, n° 2, prop. 4, we obtain modC(z)=∣z∣2\mathrm{mod}_\mathbf{C}(z) = |z|^2 for all z∈Cz \in \mathbf{C}. (2)

2) Take K=RK = \mathbf{R}, and for A the quaternion field H\mathbf{H} (GT, VIII, §1, No. 4). Consider the following elements of M2(C)\mathbf{M}_2(\mathbf{C}):

X1=(0ii0)X2=(0−110)X3=(i00−i) X_1 = \begin{pmatrix} 0 & i \\ i & 0 \end{pmatrix} \quad X_2 = \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix} \quad X_3 = \begin{pmatrix} i & 0 \\ 0 & -i \end{pmatrix}

which, together with I2I_2, form a basis of M2(C)\mathbf{M}_2(\mathbf{C}) over C\mathbf{C}. One verifies easily that

X12=X22=X32=−I2,X1X2=−X2X1=X3, X_1^2 = X_2^2 = X_3^2 = -I_2, \qquad X_1 X_2 = -X_2 X_1 = X_3,
X2X3=−X3X2=X1,X3X1=−X1X3=X2. X_2 X_3 = -X_3 X_2 = X_1, \qquad X_3 X_1 = -X_1 X_3 = X_2.

The mapping a+bi+cj+dk↦aI2+bX1+cX2+dX3a + b i + c j + d k \mapsto a I_2 + b X_1 + c X_2 + d X_3 may therefore be extended to a C\mathbf{C}-isomorphism of the algebra C⊗RH\mathbf{C} \otimes_\mathbf{R} \mathbf{H} onto the algebra M2(C)\mathbf{M}_2(\mathbf{C}). Since [H:R]=4[\mathbf{H} : \mathbf{R}] = 4, C\mathbf{C} is a neutralizing field of H\mathbf{H} (Alg., chap. VIII, §10, n° 5), and the reduced norm of q=a+bi+cj+dk∈Hq = a + b i + c j + d k \in \mathbf{H} is

Nrd(q)=det⁡(aI2+bX1+cX2+dX3) \mathrm{Nrd}(q) = \det(a I_2 + b X_1 + c X_2 + d X_3)
=det⁡(a+id−c+ibc+iba−id)=a2+b2+c2+d2=∥q∥2. = \det \begin{pmatrix} a + i d & -c + i b \\ c + i b & a - i d \end{pmatrix} = a^2 + b^2 + c^2 + d^2 = \|q\|^2.

By Alg., chap. VIII, §12, n° 3, prop. 8, one has

NH/R(q)=(NrdH/R(q))2=∥q∥4. \mathrm{N}_{\mathbf{H}/\mathbf{R}}(q) = (\mathrm{Nrd}_{\mathbf{H}/\mathbf{R}}(q))^2 = \|q\|^4.

This stated, Prop. 17 shows that

modH(q)=∥q∥4. \mathrm{mod}_\mathbf{H}(q) = \|q\|^4.

A deeper study of the structure of locally compact fields will be made in CA, VI, §9.

(2) This also follows from Cor. 1 of Prop. 15 and the fact that left-multiplication by z=a+ibz = a + i b has matrix (a−bba)\begin{pmatrix} a & -b \\ b & a \end{pmatrix} with respect to the canonical basis 1,i1, i of C\mathbf{C} over R\mathbf{R}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.