*Let Xij (1≤i≤m,1≤j≤ni), Yi (1≤i≤m), and Z be locally compact spaces; for each i, let φi be a mapping of Xi=∏jXij into Yi; let φ be the product of the φi, mapping X=∏iXi into Y=∏iYi; let ψ be a mapping of Y into Z.
(i) Let μij be measures given, respectively, on the Xij, such that, for each i, the μij (1≤j≤ni) are φi-convolvable, and such that the measures ∗∣μij∣ are ψ-convolvable; then the μij, for 1≤i≤m,1≤j≤ni, are (ψ∘φ)-convolvable and
∗i,jμij=∗i(∗jμij).
(ii) Assume ψ and the φi continuous, and let μij be measures =0 given, respectively, on the Xij and (ψ∘φ)-convolvable; then, for each i, the μij (1≤j≤ni) are φi-convolvable, the measures ∗j∣μij∣ are ψ-convolvable, and the formula (3) holds.
It suffices to consider the case that all of the measures in question are ≥0.
Let us place ourselves under the hypotheses of (i). The mapping φ is proper for ⨂i,jμij, and
φ(i,j⨂μij)=i⨂φi(j⨂μij)=i⨂(∗jμij)
(Ch. V, §8, No. 5, Prop. 11). The mapping ψ∘φ is proper for ⨂i,jμij, and
(ψ∘φ)(i,j⨂μij)=ψ(i⨂(∗jμij))=∗i(∗jμij) (Ch. V, §6, Prop. 4). Therefore the
μij (
1≤i≤m, 1≤j≤ni) are
(ψ∘φ)-convolvable and formula (3) holds.
Let us place ourselves under the hypotheses of (ii). First of all, Lemma 2 proves that φ is proper for ⨂i,jμij. Lemma 1 then proves that for every i, φi is proper for ⨂jμij, and that
φ(i,j⨂μij)=i⨂(∗jμij). By Lemma 2,
ψ is proper for
⨂i(∗jμij). Whence the proposition.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.