— Let f be a positive function and (gn)n≥1 a sequence of μ-measurable positive functions on T. Setting g=∑n≥1gn, one has
μ∙(fg)=n≥1∑μ∙(fgn).
Set hn=∑i=1ngi for all n≥1. For every compact subset K of T,
μK∙((fhn)K)=i=1∑nμK∙((fgi)K)
by Prop. 2 of Ch. V, §1, No. 1 applied to the compact space K. Passing to the limit with respect to the increasing directed set of compact subsets of T, one obtains
μ∙(fhn)=i=1∑nμ∙(fgi).
Now, fg is the limit of the increasing sequence (fhn)n≥1, whence μ∙(fg)=limn→∞μ∙(fhn); the preceding formula then immediately implies (4).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.