*Let g be a Lie algebra. For all x∈g, adx is a derivation. The mapping x↦adx is a homomorphism of the Lie algebra g into the Lie algebra d of derivations of g. If D∈d and x∈g, [D,adx]=ad(Dx).
Identity (4) can be written:
(adx)⋅[y,z]=[(adx)⋅y,z]+[y,(adx)⋅z]
or:
(ad[x,y])⋅z=(adx)⋅((ady)⋅z)−(ady)⋅((adx)⋅z)
whence the first two assertions. On the other hand, if D∈d, x∈g, y∈g, then [D,adx]⋅y=D([x,y])−[x,Dy]=[Dx,y]=(adDx)⋅y, whence the last assertion.
The mapping adx is also called the inner derivation defined by x.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.
Nothing.