Bourbaki

Proposition 7

Tag 0A23, permanent. Cite it as [Bourbaki, Tag 0A23].

Lie Groups and Lie Algebras, chapter II, § 1. Enveloping bigebra of a Lie algebra

There exists on the algebra UU one and only one coproduct cc which makes UU into a bigebra such that the elements of σ(g)\sigma(g) are primitive. The bigebra (U,c)(U, c) is cocommutative; its counit is the linear form ε\varepsilon such that the constant term (Chapter I, § 2, no. 1) of every element xx of UU is ε(x).1\varepsilon(x) . 1. The canonical filtration (Un)n≥0(U_n)_{n \geq 0} of UU is compatible with this bigebra structure.

(a) Let x∈gx \in g; we write c0(x)=σ(x)⊗1+1⊗σ(x)∈U⊗Uc_0(x) = \sigma(x) \otimes 1 + 1 \otimes \sigma(x) \in U \otimes U. If x,yx, y are in gg, then

c0(x)c0(y)=(σ(x)σ(y))⊗1+1⊗(σ(x)σ(y))+σ(x)⊗σ(y)+σ(y)⊗σ(x), c_0(x)c_0(y) = (\sigma(x)\sigma(y)) \otimes 1 + 1 \otimes (\sigma(x)\sigma(y)) + \sigma(x) \otimes \sigma(y) + \sigma(y) \otimes \sigma(x),
whence
[c0(x),c0(y)]=c0([x,y]). [c_0(x), c_0(y)] = c_0([x, y]).
By the universal property of UU (Chapter I, § 2, no. 1, Proposition 1), there exists one and only one unital algebra homomorphism
c:U→U⊗U c : U \to U \otimes U
such that c(σ(x))=σ(x)⊗1+1⊗σ(x)c(\sigma(x)) = \sigma(x) \otimes 1 + 1 \otimes \sigma(x) for x∈gx \in g. This proves the uniqueness assertion of Proposition 7.

(b) We show that cc is coassociative. The linear mappings c′c' and c′′c'' of UU into U⊗U⊗UU \otimes U \otimes U defined by

c′=(c⊗IdU)∘candc′′=(IdU⊗c)∘c c' = (c \otimes \mathrm{Id}_U) \circ c \quad \text{and} \quad c'' = (\mathrm{Id}_U \otimes c) \circ c
are unital algebra homomorphisms which coincide on σ(g)\sigma(g) since, for a∈σ(g)a \in \sigma(g),
c′(a)=a⊗1⊗1+1⊗a⊗1+1⊗1⊗a=c′′(a), c'(a) = a \otimes 1 \otimes 1 + 1 \otimes a \otimes 1 + 1 \otimes 1 \otimes a = c''(a),
whence the result.

(c) We show that cc is cocommutative. Let τ\tau be the automorphism of U⊗UU \otimes U such that τ(a⊗b)=b⊗a\tau(a \otimes b) = b \otimes a for a,ba, b in UU. The mappings τ∘c\tau \circ c and cc of UU into U⊗UU \otimes U are unital algebra homomorphisms which coincide on σ(g)\sigma(g), whence the result.

(d) We show that ε\varepsilon is a counit for cc. The mappings (IdU⊗ε)∘c(\mathrm{Id}_U \otimes \varepsilon) \circ c and (ε ⊗ Id_U) ∘ c, of U into U are unital algebra homomorphisms which coincide with Id_U on σ(g).

(e) We know that U_0 = K . 1, U_n ⊂ U_{n+1}, U = ⋃_{n ≥ 0} U_n and U_n · U_m ⊂ U_{n+m} (Chapter I, § 2, no. 6). Let a_1, ..., a_n be in σ(g). Then

c(a1...an)=∏i=1nc(ai)=∏i=1n(ai⊗1+1⊗ai) c(a_1 ... a_n) = \prod_{i=1}^n c(a_i) = \prod_{i=1}^n (a_i \otimes 1 + 1 \otimes a_i)
=∑i=0n∑α∈I(i)(aα(1)...aα(i))⊗(aα(i+1)...aα(n)), = \sum_{i=0}^n \sum_{\alpha \in I(i)} (a_{\alpha(1)} ... a_{\alpha(i)}) \otimes (a_{\alpha(i+1)} ... a_{\alpha(n)}),

where I(i) denotes the set of permutations of {1, n} which are increasing in each of the intervals {1, i} and {i + 1, n}. As U_n is the K-module generated by the products of at most n elements of σ(g), formula (8) implies that the filtration (U_n) is compatible with the bigebra structure of (U, c).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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