Let G be a Lie group, U an open neighbourhood of e, E a complete normed space and ϕ:U→E a chart of the manifold G. There exists a neighbourhood W of e contained in U such that ϕ∣W is an isomorphism of W (with the right uniform structure) onto ϕ(W) (with the uniform structure induced by that on E).
It can be assumed that ϕ(e)=0. Let U′=ϕ(U). Let ψ:U′→U be the inverse mapping of ϕ. Let V be a symmetric open neighbourhood of e such that V2⊂U and let V′=ϕ(V). We define mappings θ1,θ2 of V′×V′ into V′×U′ as follows:
θ1(x,y)θ2(x,y)=(x,ϕ(ψ(x)ψ(y)−1))=(x,ϕ(ψ(y)−1ψ(x))). It is immediately verified that
θ2(θ1(x,y))=θ1(θ2(x,y))=(x,y) for
x,y sufficiently close to 0. On the other hand,
θ1 and
θ2 are analytic and hence strictly differentiable at
(0,0). Therefore (
Differentiable and Analytic Manifolds, R, 1.2.2) there exist a neighbourhood
W′ of 0 in
V′ and constants
a>0,b>0 such that
a(∥x1−x2∥+∥ϕ(ψ(x1)ψ(y1)−1)−ϕ(ψ(x2)ψ(y2)−1)∥)≤∥x1−x2∥+∥y1−y2∥≤b(∥x1−x2∥+∥ϕ(ψ(x1)ψ(y1)−1)−ϕ(ψ(x2)ψ(y2)−1)∥)
for all x1,x2,y1,y2 in W′. Writing x1=x2=y2, we obtain
(2)a∥ϕ(ψ(x1)ψ(y1)−1)∥≤∥x1−y1∥≤b∥ϕ(ψ(x1)ψ(y1)−1)∥.
For δ>0, let Nδ be the set of ordered pairs (x,y)∈W′×W′ such that ∥x−y∥≤δ. The Nδ form a fundamental system of entourages in W′. We write W=ψ(W′). Let Mδ be the set of ordered pairs (u,v)∈W×W such that ∥ϕ(uv−1)∥≤δ. The Mδ form a fundamental system of entourages in W with the right uniform structure. But relation (2) proves that
Nδ⊂(ϕ×ϕ)(Ma−1δ),(ϕ×ϕ)(Mδ)⊂Nbδ
and hence W has the property of the lemma.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.