Bourbaki

Corollary 2

Tag 0ACT, permanent. Cite it as [Bourbaki, Tag 0ACT].

Lie Groups and Lie Algebras, chapter III, § 4. Passage from Lie algebras to Lie groups

Let k be a non-discrete closed subfield of K, G a Lie group over k and L = L(G). Suppose that L has a normable Lie K-algebra structure L', compatible with the normable Lie k-algebra structure and invariant under the adjoint representation of G. Then there exists on G one and only one Lie K-group structure compatible with the Lie k-group structure and for which the Lie algebra is L'.

There exists a Lie group germ G1G_1 over K such that L(G1)=L′L(G_1) = L' (Theorem 2). By Corollary 1 to Theorem 1 of no. 1, G and G1G_1, considered as Lie k-group germs, are locally isomorphic. Hence there exist an open neighbourhood G' of e in G and a Lie K-group germ structure on G', with Lie algebra L, which is compatible with the Lie group germ structure over k. Let V be a symmetric open neighbourhood of e in G such that V2⊂G′V^2 \subset G'. Let g∈Gg \in G. Then ϕ=Int⁡g\phi = \operatorname{Int} g is a k-isomorphism of a sufficiently small open Lie subgroup germ of G' onto an open Lie subgroup germ of G'; and Te(ϕ)T_e(\phi) is K-linear and hence Tx(ϕ)T_x(\phi) is K-linear for x sufficiently close to e; therefore the restriction of Int g to a sufficiently small open neighbourhood of e in V is K-analytic (Differentiable and Analytic Manifolds, R, 5.14.6). By § 1, no. 9, Proposition 18, there exists on G an analytic K-manifold structure with which G is a Lie

K-group and V is an open sub-K-manifold of G. By translation, it is seen that the underlying k-manifold structure of G is the given structure. The Lie algebra of the Lie K-group G is the same as that of the open Lie K-subgroup germ V and hence is L'. Finally, the uniqueness stated in the corollary follows from § 3, no. 8, Proposition 32.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.