Bourbaki

Corollary 2

Tag 0AEI, permanent. Cite it as [Bourbaki, Tag 0AEI].

Lie Groups and Lie Algebras, chapter III, § 6. Real and complex Lie groups

Let G be a Lie group and H1 and H_2 integral subgroups of G. If L(H2)⊂L(H1)L(H_2) \subset L(H_1), then H_2 is an integral subgroup of H_1.*

Let i1:H1→G,i2:H2→Gi_1 : H_1 \to G, i_2 : H_2 \to G be the canonical injections. Then

L(i2)(L(H2))=L(H2)⊂L(H1). L(i_2)(L(H_2)) = L(H_2) \subset L(H_1).
By Proposition 1, i2i_2 is an analytic mapping of H2H_2 into H1H_1 and even an immersion of H2H_2 into H1H_1 since L(i2)L(i_2) is an isomorphism of L(H2)L(H_2) onto a subalgebra of L(H1)L(H_1) admitting a topological supplement.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.