Bourbaki

Corollary 2

Tag 0AIK, permanent. Cite it as [Bourbaki, Tag 0AIK].

Lie Groups and Lie Algebras, chapter III, § 9. Commutators, centralizers and normalizers in a Lie group

Let G be a Hausdorff topological group and A a subgroup of G. For A to be solvable (resp. nilpotent, commutative, it is necessary and sufficient that A‾\overline{A} be so.

§ 9.2

This follows immediately from Proposition 1.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.