Proposition 1
Tag 0AL9, permanent. Cite it as [Bourbaki, Tag 0AL9].
Lie Groups and Lie Algebras, chapter III, § 10. The automorphism group of a Lie group
Let K' be a non-discrete closed subfield of K, G a Lie group over K, V a manifold over K' and a K'-*analytic mapping of* V G into G. Suppose that, for all , the mapping of G into G is an automorphism of G. Let be an element of V such that for all and . Then the vector field on G is an infinitesimal automorphism of G.
For . Hence, for (§ 2, no. 1, Proposition 3). In particular, the mapping of G into TG is a group homomorphism. On the other hand, this mapping is analytic by Lemma 2.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Cited by
Nothing.