Bourbaki

Proposition 3

Tag 0BZO, permanent. Cite it as [Bourbaki, Tag 0BZO].

General Topology, chapter VII, § 3. Infinite sums in the groups $\mathbf{R}^n$

Let (xλ)λ∈L(x_\lambda)_{\lambda \in L} be a summable family of points of Rm\mathbf{R}^m, (yμ)μ∈M(y_\mu)_{\mu \in M} a summable family of points of Rn\mathbf{R}^n, and let ff be a bilinear mapping of Rm×Rn\mathbf{R}^m \times \mathbf{R}^n into Rp\mathbf{R}^p. Then the family (f(xλ,yμ))(λ,μ)∈L×M(f(x_\lambda, y_\mu))_{(\lambda, \mu) \in L \times M} is summable and we have

∑(λ,μ)∈L×Mf(xλ,yμ)=f(∑λ∈μxλ,∑μ∈Myμ). \sum_{(\lambda, \mu) \in L \times M} f(x_\lambda, y_\mu) = f \left( \sum_{\lambda \in \mu} x_\lambda, \sum_{\mu \in M} y_\mu \right).

To show that the family (f(xλ,yμ))(f(x_\lambda, y_\mu)) is summable, it is sufficient by Proposition 1 to establish that each of the pp families formed by the coordinates of the points f(xλ,yμ)f(x_\lambda, y_\mu) in Rn\mathbf{R}^n is summable: in other words, we can restrict ourselves to the case where ff is a bilinear form; but for such a form ff we have

f(x,y)=∑i,jaijxiyj, f(x, y) = \sum_{i, j} a_{ij} x_i y_j,

and therefore we are brought back to the case f(x,y)=xiyjf(x, y) = x_i y_j, and in this case the result has already been proved (Chapter IV, § 7, no. 3, Proposition 1).

By specializing the function ff we obtain in particular the following corollaries:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.