Lemma 2
Tag 0CAE, permanent. Cite it as [Bourbaki, Tag 0CAE].
General Topology, chapter IX, Appendix 0. Infinite products in normed algebras
If is a finite subset of such that , then
For since for every subset of , we have from (2)
and since also , from (1), it follows that
which leads to the result.
Now let be a multipliable sequence in , whose product is a unit; by Theorem 1 there exists a finite subset of such that, for each finite subset of which does not meet , we have
By Lemma 2, it follows that for every finite subset of which does not meet , and hence (Chapter IV, § 7, no. 1, Theorem 1) the family is summable in .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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