Bourbaki

Remark 2

Tag 0CJO, permanent. Cite it as [Bourbaki, Tag 0CJO].

Commutative Algebra, chapter VIII, § 1. Dimension de Krull d’un anneau

If Y is a nonempty closed subset of X, one has codim⁡(Y,X)≤dim⁡(X)\operatorname{codim}(Y, X) \leq \dim(X). One has dim⁡(X)=sup⁡Ycodim⁡(Y,X)\dim(X) = \sup_Y \operatorname{codim}(Y, X), where Y runs through the set of irreducible closed subsets of X. If Y and Y’ are two closed subsets of X such that Y′⊂YY' \subset Y, one has codim⁡(Y,X)≤codim⁡(Y′,X)\operatorname{codim}(Y, X) \leq \operatorname{codim}(Y', X).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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