Bourbaki

Proposition 10

Tag 0CKN, permanent. Cite it as [Bourbaki, Tag 0CKN].

Commutative Algebra, chapter VIII, § 1. Dimension de Krull d’un anneau

The sequences of Z\mathbf{Z}-modules and homomorphisms

K(C≤d−1)→idK(C≤d)→ζdZd⟶0K(C>d+1)→idK(C>d)→ζdZd⟶0 \begin{array}{cccccc} K(\mathscr{C}_{\leq d-1}) & \xrightarrow{i_d} & K(\mathscr{C}_{\leq d}) & \xrightarrow{\zeta_d} & Z_d & \longrightarrow 0 \\ K(\mathscr{C}^{>d+1}) & \xrightarrow{i_d} & K(\mathscr{C}^{>d}) & \xrightarrow{\zeta_d} & Z^d & \longrightarrow 0 \end{array}

are exact.

One has ζd∘id=0\zeta_d \circ i_d = 0 by Lemma 1. For every p∈Spec(A)p \in \mathrm{Spec}(A) such that dim⁡(A/p)=d\dim(A/p) = d, one has ζd([A/p]≤d)=zd(A/p)=[V(p)]\zeta_d([A/p]_{\leq d}) = z_d(A/p) = [V(p)], hence the homomorphism ζd\zeta_d is surjective. By IV, § 1, No. 4, Theorem 1, K(C≤d)K(\mathscr{C}_{\leq d}) is generated by the [A/p]≤d[A/p]_{\leq d}, where p∈Spec(A)p \in \mathrm{Spec}(A) and dim⁡(A/p)≤d\dim(A/p) \leq d; consequently, every element ξ\xi of K(C≤d)K(\mathscr{C}_{\leq d}) can be written ξ=id(η)+∑i=1kni[A/pi]≤d\xi = i_d(\eta) + \sum_{i=1}^k n_i[A/p_i]_{\leq d}, with η∈K(C≤d−1)\eta \in K(\mathscr{C}_{\leq d-1}), ni∈Zn_i \in \mathbf{Z} and dim⁡(A/pi)=d\dim(A/p_i) = d for 1≤i≤k1 \leq i \leq k; one has ζd(ξ)=∑i=1kni[V(pi)]\zeta_d(\xi) = \sum_{i=1}^k n_i[V(p_i)] and consequently ζd(ξ)=0\zeta_d(\xi) = 0 implies ξ=id(η)∈Im(id)\xi = i_d(\eta) \in \mathrm{Im}(i_d), whence Ker(ζd)=Im(id)\mathrm{Ker}(\zeta_d) = \mathrm{Im}(i_d).

One reasons analogously for the second sequence.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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