Bourbaki

Corollary 1

Tag 0CMT, permanent. Cite it as [Bourbaki, Tag 0CMT].

Commutative Algebra, chapter VIII, § 3. Dimension des anneaux noethériens

a) Every noetherian local ring is finite-dimensional. More generally, every nonzero noetherian semi-local ring (II, § 3, No. 5, def. 4) is finite-dimensional. b) Let AA be a noetherian ring. Every ideal of AA, distinct from AA, is of finite height. c) Every decreasing sequence of prime ideals of a noetherian ring AA is stationary.

a) Let AA be a nonzero semi-local noetherian ring and aa its radical; the quotient ring A/aA/a is artinian and nonzero, hence of dimension 0 (§1§ 1, No. 3, Example 1). There exists an integer m⩾0m \geqslant 0 such that the ideal aa of AA is generated by mm elements; hence 0⩽dim⁡(A)⩽m0 \leqslant \dim(A) \leqslant m by Prop. 2. b) Let a≠Aa \neq A be an ideal of AA, and let mm be a maximal ideal of AA containing aa. We have 0⩽ht(a)⩽dim⁡(Am)0 \leqslant \mathrm{ht}(a) \leqslant \dim(A_m) by Prop. 7 of §1§ 1, No. 3, and AmA_m is a local noetherian ring. Hence ht(a)\mathrm{ht}(a) is finite by a). c) Every finite strictly decreasing sequence (pi)0⩽i⩽n(p_i)_{0 \leqslant i \leqslant n} of prime ideals of AA defines a chain pn⊂...⊂p0p_n \subset ... \subset p_0, whence n⩽dim⁡(Ap0)<+∞n \leqslant \dim(A_{p_0}) < + \infty. Therefore there cannot exist an infinite strictly decreasing sequence of prime ideals of AA, whence c).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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