Bourbaki

Lemma 3

Tag 0CRE, permanent. Cite it as [Bourbaki, Tag 0CRE].

Commutative Algebra, chapter VIII, § 6. Dimension des anneaux gradués

Suppose that HH is generated by H0∪H1H_0 \cup H_1 and MM generated by ⨁i≤n0Mi\bigoplus_{i \leq n_0} M_i for a suitable integer n0n_0. Then the filtration (S−1M≥n)(S^{-1}M_{\geq n}) on S−1MS^{-1}M is good for the ideal S−1H≥1S^{-1}H_{\geq 1} of S−1HS^{-1}H.

One has, for n≥n0n \geq n_0, M≥n+1=H1⋅M≥nM_{\geq n+1} = H_1 \cdot M_{\geq n}, hence S−1M≥n+1=H1⋅S−1M≥n=S−1H≥1⋅S−1M≥nS^{-1}M_{\geq n+1} = H_1 \cdot S^{-1}M_{\geq n} = S^{-1}H_{\geq 1} \cdot S^{-1}M_{\geq n}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Translated with machine help, not yet reviewed by a person.