Bourbaki

Proposition 6

Tag 0CRJ, permanent. Cite it as [Bourbaki, Tag 0CRJ].

Commutative Algebra, chapter VIII, § 6. Dimension des anneaux gradués

Suppose H0H_0 local and artinian, HH finitely generated as an H0H_0-algebra and MM finitely generated as an HH-module.

a) Let a1,...,ana_1, ..., a_n be elements of HH, homogeneous of degrees >0> 0, and let φ\varphi be the homomorphism (of H0H_0-algebras) of H0[X1,...,Xn]H_0[X_1, ..., X_n] into HH which maps XiX_i to aia_i for 1≤i≤n1 \leq i \leq n. The S−1HS^{-1}H-module S−1M/∑i=1n(ai/1).S−1MS^{-1}M / \sum_{i=1}^n (a_i/1).S^{-1}M is of finite length if and only if φ∗(M)\varphi_*(M) is a finitely generated module over H0[X1,...,Xn]H_0[X_1, ..., X_n].

b) There exists a family (a1,...,ad)(a_1, ..., a_d) of elements of HH, all homogeneous of the same degree >0> 0, with d=dim⁡H(M)d = \dim_H(M), and such that (a1/1,...,ad/1)(a_1/1, ..., a_d/1) is a maximal secant sequence for the S−1HS^{-1}H-module S−1MS^{-1}M. If moreover HH is generated by H1H_1 as an H0H_0-algebra, and if the residue field of H0H_0 is infinite, one can take the aia_i of degree 1.

a) Put N=M/∑i=1naiMN = M / \sum_{i=1}^n a_i M. We have dim⁡H(N)=dim⁡S−1H(S−1N)\dim_H(N) = \dim_{S^{-1}H}(S^{-1}N) by prop. 4. Consequently, the S−1HS^{-1}H-module S−1NS^{-1}N is of finite length if and only if the HH-module NN is of finite length, that is to say if and only if NN is a finitely generated module over H0H_0. If φ∗(M)\varphi_*(M) is the module over H0[X1,...,Xn]H_0[X_1, ..., X_n] deduced from MM by the homomorphism φ:H0[X1,...,Xn]→M\varphi : H_0[X_1, ..., X_n] \to M, we have N=φ∗(M)/∑i=1nXi⋅φ∗(M)N = \varphi_*(M)/\sum_{i=1}^n X_i \cdot \varphi_*(M). Consequently (A, II, p. 171, cor. 3 and remark) φ∗(M)\varphi_*(M) is a finitely generated module over H0[X1,...,Xn]H_0[X_1, ..., X_n] if and only if NN is a finitely generated module over H0H_0. This proves a).

To prove b), we shall first establish a lemma.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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