Let ρ:B→A be a ring homomorphism satisfying the conditions of Lemma 3 of No. 4. Then W(ρ):W(B)→W(A) is a surjective homomorphism of rings, and ΦB:W(B)→BN is an injective homomorphism. It is therefore enough to prove that one has
whatever b in W(B) and the integers m⩾1,n⩾0 may be. Now one has
Φn(b0,...,bm−1,...)=Φn(b0,...,bn)if0⩽n<m
=i=0∑m−1pi⋅bipn−iifm⩽n
Φn(0,...,0,bm,bm+1,...)=0if0⩽n<m
=i=m∑npi⋅bipn−iifm⩽n,
whence formula (35).
Soit A a ring. For every integer m⩾0, denote by Vm(A) the set of Witt vectors a=(an)n∈N such that an=0 for 0⩽n<m. It is the image of the m-th power Vm of the mapping VA. The formulas
(36)
Vm(a+b)=Vm(a)+Vm(b)
(37)
Vm(a)×b=Vm(a×Fm(b))
result from prop. 3 of No. 5 by induction on m. They imply that Vm(A) is an ideal of W(A).
In what follows, we shall endow W(A) with the topology T associated with the filtration (Vm(A))m∈Z. Since Vm(A) is an ideal of W(A) for every m∈Z, the topology T is compatible with the ring structure of W(A) (TG, III, p. 49, example 3). Let a∈W(A); the sets a+Vm(A), where m runs through N, form a fundamental system of neighbourhoods of a for T. Now, it follows from lemma 4 that a+Vm(A) consists of the Witt vectors b such that ai=bi for 0≤i<m. Consequently, T is none other than the product topology on AN of the discrete topology on each of the factors, and W(A) is therefore a separated and complete topological ring (TG, II, p. 17, prop. 10 and TG, III, p. 22, prop. 4).
Let us denote by τA (or simply τ) the mapping of A into W(A) which associates with an element a of A(a,0,0,...) . We have Φn(τ(a))=apn for every n∈N. For every ring homomorphism ρ:B→A, we have W(ρ)∘τB=τA∘ρ.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.