Bourbaki

Example 2

Tag 0CUF, permanent. Cite it as [Bourbaki, Tag 0CUF].

Commutative Algebra, chapter IX, § 1. Vecteurs de Witt

Let us make explicit the operations in W2(A)W_2(A). We have

[a0,a1]+[b0,b1]=[a0+b0,a1+b1−∑i=1p−11p(pi)a0ib0p−i] [a_0, a_1] + [b_0, b_1] = \left[ a_0 + b_0, a_1 + b_1 - \sum_{i=1}^{p-1} \frac{1}{p} \binom{p}{i} a_0^i b_0^{p-i} \right]
[a0,a1]×[b0,b1]=[a0b0,a0pb1+a1b0p+p⋅a1b1] [a_0, a_1] \times [b_0, b_1] = [a_0 b_0, a_0^p b_1 + a_1 b_0^p + p \cdot a_1 b_1]

for [a0,a1][a_0, a_1] and [b0,b1][b_0, b_1] in W2(A)W_2(A). The ghost components of [a0,a1][a_0, a_1] are a0a_0 and a0p+p⋅a1a_0^p + p \cdot a_1.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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