Bourbaki

Example 2

Tag 0D2E, permanent. Cite it as [Bourbaki, Tag 0D2E].

Commutative Algebra, chapter X, § 2. Modules et anneaux macaulayens

Let M′M' be a direct factor submodule of a finitely generated Macaulay AA-module MM. Then M′M' is Macaulay; in fact, for every maximal ideal mm of AA, the AmA_m-module Mm′M'_m is a direct factor of MmM_m and one consequently has

profAm(Mm′)≥profAm(Mm)≥dim⁡Am(Mm)≥dim⁡Am(Mm′), \mathrm{prof}_{A_m}(M'_m) \geq \mathrm{prof}_{A_m}(M_m) \geq \dim_{A_m}(M_m) \geq \dim_{A_m}(M'_m),
by Remark 4 of §1§ 1, No. 1 and VIII, §1§ 1, No. 4, Proposition 9 c).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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