Bourbaki

Proposition 9

Tag 0D3E, permanent. Cite it as [Bourbaki, Tag 0D3E].

Commutative Algebra, chapter X, § 2. Modules et anneaux macaulayens

Let ρ : A → B be a homomorphism of noetherian rings, M a finitely generated A-module and N a finitely generated B-module, flat over A. Denote by aρ:Spec(B)⟶Spec(A)^a\rho : \mathrm{Spec}(B) \longrightarrow \mathrm{Spec}(A) the mapping associated with ρ. The following conditions are equivalent:

(i) the B-module M⊗ANM \otimes_A N is Macaulay; (ii) the (κ(p)⊗AB)(\kappa(p) \otimes_A B)-module κ(p)⊗AN\kappa(p) \otimes_A N is Macaulay for every p∈SuppA(M)p \in \mathrm{Supp}_A(M), and the ApA_p-module MpM_p is Macaulay for every p∈aρ(SuppB(N))p \in ^a\rho(\mathrm{Supp}_B(N)); (iii) for every maximal ideal of SuppB(N)\mathrm{Supp}_B(N) whose inverse image pp in A belongs to SuppA(M)\mathrm{Supp}_A(M), the ApA_p-module MpM_p and the (κ(p)⊗AB)(\kappa(p) \otimes_A B)-module κ(p)⊗AN\kappa(p) \otimes_A N are Macaulay.

If moreover the B-module N is faithfully flat, these conditions imply that the A-module M is Macaulay.

Let q be a prime ideal of B belonging to the support of M⊗ANM \otimes_A N. Put p=ρ−1(q)p = \rho^{-1}(q). Since the module (M⊗AN)q(M \otimes_A N)_q is identified with Mp⊗ApNqM_p \otimes_{A_p} N_q, the modules MpM_p and NqN_q are non-zero, and the same is true of κ(p)⊗ANq\kappa(p) \otimes_A N_q (No. 6, Remark). The ApA_p-module NqN_q, being isomorphic to a module of fractions of NpN_p, is flat and we have the equalities

profBq((M⊗AN)q)=profAp(Mp)+profBq(κ(p)⊗ANq) \mathrm{prof}_{B_q}((M \otimes_A N)_q) = \mathrm{prof}_{A_p}(M_p) + \mathrm{prof}_{B_q}(\kappa(p) \otimes_A N_q)
dim⁡Bq((M⊗AN)q)=dim⁡Ap(Mp)+dim⁡Bq(κ(p)⊗ANq) \dim_{B_q}((M \otimes_A N)_q) = \dim_{A_p}(M_p) + \dim_{B_q}(\kappa(p) \otimes_A N_q)

(§ 1, No. 6, prop. 11, b) and remark), in which each term is an integer ≥0\geq 0. Taking into account the fact that the BqB_q-module κ(p)⊗ANq\kappa(p) \otimes_A N_q is a Macaulay module if and only if it is so as a (κ(p)⊗ABq)(\kappa(p) \otimes_A B_q)-module (No. 1, example 4), we deduce the equivalence of the following two conditions:

(α) the BqB_q-module (M⊗AN)q(M \otimes_A N)_q is a Macaulay module; (β) the ApA_p-module MpM_p and the (κ(p)⊗ABq)(\kappa(p) \otimes_A B_q)-module κ(p)⊗ANq\kappa(p) \otimes_A N_q are Macaulay modules.

Let us now prove that (iii) implies (i). Let n be a maximal ideal of B belonging to the support of M⊗ANM \otimes_A N, and let p=ρ−1(n)p = \rho^{-1}(n). From the foregoing we have p∈SuppA(M)∩aρ(SuppB(N))p \in \mathrm{Supp}_A(M) \cap ^a\rho(\mathrm{Supp}_B(N)); condition (iii) and the remark of No. 6 imply that condition (β) above is satisfied with q=nq = n. It follows that the BnB_n-module (M⊗AN)n(M \otimes_A N)_n is a Macaulay module, whence (i).

The implication (ii) ⇒ (iii) is clear; let us prove that (i) implies (ii). Suppose the B-module M ⊗_A N to be a Macaulay module. Let p be an element of Supp_A(M). We may suppose that the (κ(p) ⊗_A B)-module κ(p) ⊗_A N is nonzero, that is to say, that there exists a prime ideal q of Supp_B(N) lying over p (No. 6, remark). The B_q-module (M ⊗_A N)_q is a Macaulay module (No. 1, example 3); it follows from implication (α) ⇒ (β) proved above and from the remark of No. 6 that the A_p-module M_p and the (κ(p) ⊗_A B)-module (κ(p) ⊗_A N) are Macaulay modules, whence (ii).

If moreover N is faithfully flat over A, we have κ(p) ⊗_A N ≠ 0 for every p ∈ Spec(A), whence a_p(Supp_B(N)) = Spec(A) (No. 6, remark), so that (ii) implies that M is a Macaulay module.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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