Corollary 4
Tag 0D3I, permanent. Cite it as [Bourbaki, Tag 0D3I].
Commutative Algebra, chapter X, § 2. Modules et anneaux macaulayens
Let A be a noetherian ring, J an ideal of A and M a finitely generated A-module. Denote by Ā and Ĝ the separated completions of A and M for the J-adic topology, and by S the multiplicative subset 1 + J of Λ. Consider the following conditions:
(i) the A-module M is a Macaulay module; (ii) the Ā-module Ĝ is a Macaulay module; (iii) the S^{-1}A-module S^{-1}M is a Macaulay module; (iv) for every maximal ideal m ∈ Supp(M) ∩ V(J), the A_m-module M_m is a Macaulay module; (v) for every prime ideal p ∈ Supp(M) such that p + J ≠ A, the Λ_p-module M_p is a Macaulay module and the ring κ(p) ⊗_A Ā is a Macaulay ring.
Conditions (ii) to (v) are equivalent, and are implied by (i). When the ideal J is contained in the radical of A, conditions (i) to (v) are equivalent.
We know that (i) implies (iii) (No. 1, example 3), and (iii) is identical with (i) when J is contained in the radical of A (since the elements of S are then invertible).
It is clear that (v) implies (iv) and that (iv) implies (i).
(i) (ii) : Let be a maximal ideal of ; then is a maximal ideal of lying over , and every maximal ideal of is obtained in this way (III, § 3, No. 4, prop. 8). The ring is a field, hence a Macaulay ring; if the -module is a Macaulay module, the same is true of the -module by implication (iii) (i) of prop. 9.
(ii) (v) : The -module is isomorphic to (III, § 3, No. 4, th. 3); if it is a Macaulay module, it follows from prop. 9, (i) (ii) that is a Macaulay ring for every , and that the -module is a Macaulay module.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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