Bourbaki

Remark 2

Tag 0D4A, permanent. Cite it as [Bourbaki, Tag 0D4A].

Commutative Algebra, chapter X, § 3. Profondeur et dimension homologique

Let A be a noetherian local ring, M a finitely generated A-module of finite projective dimension nn, N a nonzero finitely generated A-module. The A-module Ext⁡An(M,N)\operatorname{Ext}_A^n(M, N) is nonzero: let in fact L be a minimal projective resolution of M, and d its differential. We have an exact sequence

Hom⁡A(Ln−1,N)→Hom⁡(dn,1)Hom⁡A(Ln,N)⟶Ext⁡An(M,N)→0. \operatorname{Hom}_A(L_{n-1}, N) \xrightarrow{\operatorname{Hom}(d_n, 1)} \operatorname{Hom}_A(L_n, N) \longrightarrow \operatorname{Ext}_A^n(M, N) \to 0 .

Since dn⊗1κAd_n \otimes 1_{\kappa_A} is zero, one deduces from this, by tensor product with κA\kappa_A, an isomorphism κA⊗AHomA(Ln,N)⟶κA⊗AExtAn(M,N)\kappa_A \otimes_A \mathrm{Hom}_A(L_n, N) \longrightarrow \kappa_A \otimes_A \mathrm{Ext}_A^n(M, N), whence, taking account of formula (1) above,

[κA⊗AExtAn(M,N):κA]=[ExtAn(M,κA):κA][κA⊗AN:κA], [\kappa_A \otimes_A \mathrm{Ext}_A^n(M, N) : \kappa_A] = [\mathrm{Ext}_A^n(M, \kappa_A) : \kappa_A][\kappa_A \otimes_A N : \kappa_A],

which is nonzero by Prop. 4 and Nakayama's lemma. Consequently, the projective dimension of M is the largest integer ii such that ExtAi(M,N)\mathrm{Ext}_A^i(M, N) is nonzero.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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