Bourbaki

Example 1

Tag 0DAT, permanent. Cite it as [Bourbaki, Tag 0DAT].

Commutative Algebra, chapter X, § 8. Dualité des modules de longueur finie

Let JJ be a Matlis AA-module. Put T(M)=Hom⁡A(M,J)T(M) = \operatorname{Hom}_A(M, J) for every AA-module MM of finite length and T(f)=Hom⁡A(f,1J)T(f) = \operatorname{Hom}_A(f, 1_J) for every AA-linear mapping ff between AA-modules of finite length. Then conditions FD 1) to FD 5) are satisfied. We shall see below (th. 3) that every construction satisfying conditions FD 1) to FD 5) is obtained in this way.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Translated with machine help, not yet reviewed by a person.