Proposition 5
Tag 0DB0, permanent. Cite it as [Bourbaki, Tag 0DB0].
Commutative Algebra, chapter X, § 8. Dualité des modules de longueur finie
Let be a local homomorphism of noetherian local rings, such that the residual extension induced by is of finite degree. Let be a Matlis -module.
a) Let denote the sub--module of formed by the -homomorphisms from into whose kernel contains a power of . Then is a Matlis -module.
b) Let be a -module. The canonical mapping
defined by induces a -isomorphism of onto the sub--module of consisting of mappings such that for every element of , there exists an integer such that .
The above condition on means that is continuous when is given the discrete topology and the finest topology inducing on each finitely generated submodule the -adic topology, which justifies the notation. Analogously, the condition means that is continuous when is given the discrete topology and the -adic topology.
Let us prove a). For every -module of finite length , denote by the -module ; for every -linear mapping between -modules of finite length, denote by the -linear mapping . The verification of conditions FD 1) to FD 4) of No. 5 is immediate. Moreover, for every -module of finite length , one has ; since one has (No. 3, th. 2), one deduces that , which implies FD 5). We may therefore apply theorem 3 of No. 5; one has
so that the Matlis -module is identified with the sub--module of , which proves a).
Let us prove b). The mapping is the inverse of the canonical isomorphism
which associates to the map of into such that (A, II, p. 74, prop. 1). In order that take its values in , it is necessary and sufficient that belong to , whence b).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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