a) If the A-algebra B is finite, the B-module IB=HomA(B,IA) is a Matlis B-module.
b) If the B-module M is artinian, the mapping α is a B-isomorphism of DB(M) onto DA(M).
Proposition 5 applies in particular when A is a field k, in which case one may take IA=k, hence Dk(M)=Homkcont(M,k) ("Macaulay duality"). It will be noted that the assumption [κB:k]<+∞ is satisfied in particular when the k-algebra B is the local ring at a maximal ideal of a k-algebra of finite type (A, VIII, App. 3, cor. 1).
More particularly, consider an N-graded k-algebra of finite type S, such that S0 is a field, of finite degree over k. One may apply Proposition 5 to the local ring S′ of S at the maximal ideal S+=⨁n>0Sn or, what amounts to the same thing, to its completion S=∏n≥0Sn (III, § 1, No. 3, lemma 2 and § 2, No. 12, example 1). The S-module IS=Homkcont(S,k) is then identified with
S∗gr=n≥0⨁Homk(Sn,k)
for s∈S and u∈S∗gr, the element su of S∗gr is the interior product s⊥u (A, III, p. 156 and p. 157). Take, for example, S=k[T1,…,Td], whence S=k[[T1,…,Td]]. Let (uα)α∈Nd be the basis of the k-vector space S∗gr dual to the basis (Tα)α∈Nd of S. The structure of S∗gr as S-module is then described by the formulae (A, III, p. 167)
TβuαTβuα=uα⋅β=0if α≥β,otherwise.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.