Bourbaki

Corollary

Tag 0DB1, permanent. Cite it as [Bourbaki, Tag 0DB1].

Commutative Algebra, chapter X, § 8. Dualité des modules de longueur finie

a) If the AA-algebra BB is finite, the BB-module IB=HomA(B,IA)I_B = \mathrm{Hom}_A(B, I_A) is a Matlis BB-module.

b) If the BB-module MM is artinian, the mapping α\alpha is a BB-isomorphism of DB(M)D_B(M) onto DA(M)D_A(M).

Proposition 5 applies in particular when AA is a field kk, in which case one may take IA=kI_A = k, hence Dk(M)=Homkcont(M,k)D_k(M) = \mathrm{Hom}_k^{cont}(M, k) ("Macaulay duality"). It will be noted that the assumption [κB:k]<+∞[\kappa_B : k] < +\infty is satisfied in particular when the kk-algebra BB is the local ring at a maximal ideal of a kk-algebra of finite type (A, VIII, App. 3, cor. 1).

More particularly, consider an N\mathbf{N}-graded kk-algebra of finite type SS, such that S0S_0 is a field, of finite degree over kk. One may apply Proposition 5 to the local ring S′S' of SS at the maximal ideal S+=⨁n>0SnS_+ = \bigoplus_{n > 0} S_n or, what amounts to the same thing, to its completion S^=∏n≥0Sn\widehat{S} = \prod_{n \geq 0} S_n (III, § 1, No. 3, lemma 2 and § 2, No. 12, example 1). The SS-module IS^=Homkcont(S^,k)I_{\widehat{S}} = \mathrm{Hom}_k^{cont}(\widehat{S}, k) is then identified with

S∗gr=⨁n≥0Homk(Sn,k) S^{*gr} = \bigoplus_{n \geq 0} \mathrm{Hom}_k(S_n, k)
for s∈Ss \in S and u∈S∗gru \in S^{*gr}, the element susu of S∗grS^{*gr} is the interior product s⊥us \perp u (A, III, p. 156 and p. 157). Take, for example, S=k[T1,…,Td]S = k[T_1, \ldots, T_d], whence S^=k[[T1,…,Td]]\widehat{S} = k[[T_1, \ldots, T_d]]. Let (uα)α∈Nd(u_\alpha)_{\alpha \in \mathbf{N}^d} be the basis of the kk-vector space S∗grS^{*gr} dual to the basis (Tα)α∈Nd(T^\alpha)_{\alpha \in \mathbf{N}^d} of SS. The structure of S∗grS^{*gr} as SS-module is then described by the formulae (A, III, p. 167)

Tβuα=uα⋅βif α≥β,Tβuα=0otherwise. \begin{align*} T^\beta u_\alpha &= u_\alpha \cdot \beta & \text{if } \alpha \geq \beta , \\ T^\beta u_\alpha &= 0 & \text{otherwise}. \end{align*}

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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