Bourbaki

Proposition 6

Tag 0DB2, permanent. Cite it as [Bourbaki, Tag 0DB2].

Commutative Algebra, chapter X, § 8. Dualité des modules de longueur finie

Suppose the A-module J injective; for every A-module N, put D(N)=HomA(N,J)D(N) = \mathrm{Hom}_A(N, J).

a) The homomorphisms θi(M,P):ExtAi(M,D(P))⟶D(ToriA(M,P))\theta^i(M, P) : \mathrm{Ext}_A^i(M, D(P)) \longrightarrow D(\mathrm{Tor}_i^A(M, P)) are bijective.

b) If the ring AA is noetherian and the AA-module MM of finite type, the homomorphisms ρi(M,P):ToriA(M,D(P))⟶D(ExtAi(M,P))\rho_i(M, P) : \mathrm{Tor}_i^A(M, D(P)) \longrightarrow D(\mathrm{Ext}_A^i(M, P)) are bijective.

a) By construction, the homomorphism θ(M,P)\theta(M, P) is bijective as soon as λ(C⊗AP,J)\lambda(C \otimes_A P, J) is bijective, which is the case when JJ is injective (A, X, p. 85, Corollary 2).

b) Choose the resolution CC so that each module CpC_p is free of finite type (A, X, p. 53, Proposition 6). Then the homomorphism ν\nu is bijective, and the same is true of λ(HomgrA(C,P),J)\lambda(\mathrm{Homgr}_A(C, P), J) since JJ is injective; hence ρ(M,P)\rho(M, P) is bijective.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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