Bourbaki

Example 5

Tag 0DCR, permanent. Cite it as [Bourbaki, Tag 0DCR].

Commutative Algebra, chapter X, § 10. Cohomologie locale, dualité de Grothendieck

Let us retain the hypotheses of the preceding example and suppose moreover that dim⁡(A)=1\dim(A) = 1. Let N be a torsion A-module; since every nonzero ideal of A distinct from A is an ideal of definition (VIII, § 1, No. 3, prop. 6, e)), one has HA0(N)=NH_A^0(N) = N, and consequently HAi(N)=0H_A^i(N) = 0 for i>0i > 0 (example 2).

Let M be an A-module; let T(M)T(M) denote its torsion submodule. Consider the long exact local cohomology sequence associated with the exact sequence

0→T(M)→M→M/T(M)→0; 0 \to T(M) \to M \to M/T(M) \to 0 ;

in view of the foregoing, one deduces from it canonical isomorphisms T(M)→HA0(M)T(M) \to H_A^0(M) and HA1(M)→HA1(M/T(M))H_A^1(M) \to H_A^1(M/T(M)). Since the canonical homomorphism (K/A)⊗AM→(K/A)⊗A(M/T(M))(K/A) \otimes_A M \to (K/A) \otimes_A (M/T(M)) is bijective, one finally obtains canonical isomorphisms

HA0(M)→T(M),HA1(M)→(K/A)⊗AM. H_A^0(M) \to T(M) , \qquad H_A^1(M) \to (K/A) \otimes_A M .

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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