Let A be a local Macaulay ring, of dimension d, and let Ωbe a dualizing A-module. The homomorphismω:HAd(A)→D(Ω)is bijective.
The homomorphism ω is the limit of the inductive system of mappings (ωα)α∈Dcs, where
ωα:ExtAd(A/α,A)⟶HomA(Ω,ExtAd(A/α,Ω))
associates to an element u of ExtAd(A/α,A) the mapping x↦fx∘u (A, X, p. 114). It is therefore enough to prove that each of the mappings ωα is bijective.
Let α be an ideal of Dcs, generated by a completely secant sequence x=(x1,…,xd) for A. The Koszul complex K∙(x,A) furnishes a projective resolution of A/α; for every A-module M, the A-module Hd(HomgrA(K∙(x,A),M)) identifies canonically with M/αM (A, X, p. 155). From this one deduces an isomorphism (A, X, p. 100)
φM:M/αM⟶ExtAd(A/α,M).
Let x∈Ω. Taking account of loc. cit., p. 103, prop. 2, one has a commutative diagram
where fx is the homomorphism deduced from fx by passing to quotients. It follows that if for every A-module M one identifies ExtAd(A/α,M) with M/αM by means of φM, the homomorphism ωα is identified with the A-linear mapping of A/α into HomA(Ω,Ω/αΩ) which sends 1 to the canonical surjection, that is again with the canonical mapping A/α⟶EndA/α(Ω/αΩ). But since the A/α-module Ω/αΩ is dualizing (§ 9, No. 2, prop. 4), this mapping is bijective (§ 9, No. 4, prop. 6), which proves the proposition.
Let us identify the Matlis bidual D(D(Ω)) with Ω by the isomorphism αΩ (§ 8, No. 3, th. 2, b)).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.