Bourbaki

Example

Tag 0DD5, permanent. Cite it as [Bourbaki, Tag 0DD5].

Commutative Algebra, chapter X, § 10. Cohomologie locale, dualité de Grothendieck

Let AA be an integral noetherian local ring of dimension 1; let KK denote its field of fractions. Let Ω\Omega be a dualizing AA-module, and let MM be a finitely generated AA-module. The AA-modules HA0(M)H_A^0(M) and HA1(M)H_A^1(M) are canonically identified with T(M)T(M) and (K/A)⊗AM(K/A) \otimes_A M (No. 1, Example 5). With these identifications, the duality isomorphisms

γ0(M):T(M)⟶D(ExtA1(M,Ω)),γ1(M):(K/A)⊗AM⟶D(HomA(M,Ω))\gamma^0(M) : T(M) \longrightarrow D(\mathrm{Ext}_A^1(M, \Omega)) \quad , \quad \gamma^1(M) : (K/A) \otimes_A M \longrightarrow D(\mathrm{Hom}_A(M, \Omega))

(Theorem 1) are none other than the isomorphisms defined in § 9, No. 6.

Exercises

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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