Bourbaki

Definition 1

Tag 0DK0, permanent. Cite it as [Bourbaki, Tag 0DK0].

Algebra, chapter IX, § 2. Discriminant d'une forme sesquilinéaire

Given a sesquilinear form Φ\Phi for JJ on EE and a system S=(x1,…,xn)S = (x_1, \ldots, x_n) of nn elements of EE, the discriminant of Φ\Phi with respect to this system is called, and is denoted by DΦ(x1,…,xn)D_\Phi(x_1, \ldots, x_n) or DΦ(S)D_\Phi(S), the element det⁡(Φ(xi,xj))\det(\Phi(x_i, x_j)) of AA.

If (e1,…,en)(e_1, \ldots, e_n) is a basis of EE, the discriminant of Φ\Phi with respect to this basis is none other than the determinant of the matrix of Φ\Phi with respect to this basis.

It follows from the definition of the extension of Φ\Phi to ∧nE\wedge^n E (§1§ 1, no 9) that we have

DΦ(x1,…,xn)=Φ(n)(x1∧…∧xn,x1∧…∧xn), D_\Phi(x_1, \ldots, x_n) = \Phi_{(n)}(x_1 \wedge \ldots \wedge x_n, x_1 \wedge \ldots \wedge x_n),

where Φ(n)\Phi_{(n)} denotes the extension of Φ\Phi to ∧nE\wedge^n E. For every permutation σ∈Sn\sigma \in \mathfrak{S}_n, we therefore have

DΦ(xσ(1),…,xσ(n))=DΦ(x1,x2,…,xn). D_\Phi(x_{\sigma(1)}, \ldots, x_{\sigma(n)}) = D_\Phi(x_1, x_2, \ldots, x_n).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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