Bourbaki

Proposition 5

Tag 0DU2, permanent. Cite it as [Bourbaki, Tag 0DU2].

Algebra, chapter X, § 3. Résolutions

I(f) : I(M) → I(N) is a morphism of complexes of A-modules; one has I(f) ◦ e_M = e_N ◦ f. This is proved in a manner analogous to Prop. 4.

One has (14)

I(1M)=1I(M) I(1_M) = 1_{I(M)}
and for every homomorphism g:N→Pg : N \to P of A-modules (15)
I(g∘f)=I(g)∘I(f). I(g \circ f) = I(g) \circ I(f) .

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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