where (P,p) (resp. (P′,p′)) is a left resolution of M (resp. M′), and where the bottom horizontal line is an exact sequence. There exists a homologism p′′:Con(u)→M′′.
In fact, the exact sequence (X, p. 37, prop. 7)
0→PπCon(u)δP′(−1)→0
gives an exact homology sequence
→Hn(P)→Hn(Con(u))→Hn−1(P′)→⋯
⋯→H1(Con(u))→H0(P′)∂^H0(P)→H0(Con(u))→0.
By X, p. 38, lemma 3 a), we have ∂=−H0(u). Since Hn(P)=0=Hn(P′) for n>0 and H0(u):H0(P′)→H0(P) is identified with f:M′→M, we conclude that Hn(Con(u))=0 for n>0 and that H0(Con(u)) is isomorphic to M′′, whence the lemma.
Let us now prove the theorem.
a) Let M be an A-module of type C. For every bounded left resolution (P,p) of M of type C0, the element χC0(P) of K(C0) depends only on M. In fact, let (P1,p1) and (P2,p2) be two resolutions of this type. Consider the resolution
(P1×P2,p1×p2)
of the A-module M×M and the homomorphism Δ:x↦(x,x) of M into M×M. By lemma 4, there exists a bounded left resolution (Q,q) of M of type C0 and a commutative diagram
Qq↓MuΔP1×P2↓p1×p2M×M;
we deduce from this a commutative diagram
Qq↓Mu∘pri1MPi↓piM,i=1,2.
By lemma 5, Con (u∘pri) has zero homology, hence u∘pri is a homologism and χC0(Q)=χC0(Pi) (X, p. 41, prop. 10); it follows that χC0(P1)=χC0(P2) as announced.
b) For every A-module M of type C, let φ(M)∈K(C0) be the common value of the χC0(P) for all bounded left resolutions P of M of type C0. Let us show that the function φ:C→K(C0) is additive. Let therefore
0→M′fM→M′′→0
be an exact sequence of A-modules of type C. By Lemma 4, there exists a commutative diagram
P′p′↓0ufP↓pMgM′′→0
where (P,p) and (P′,p′) are bounded left resolutions of type C0. Then we have
c) Let then β:K(C)→K(C0) be the homomorphism such that, with the preceding notations, we have β([M]C)=χC0(P). Since p is a homomorphism, we have χC(P)=[M]C, hence α∘β([M]C)=α(χC0(P))=χC(P)=[M]C and α∘β=1K(C). If M is of type C0, then (M,1M) is a resolution of M, hence φ(M)=[M]C0 and β∘α=1K(C0), which completes the proof.
We shall apply this theorem to modules of "finite projective dimension" in § 8 (X, p. 137).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.