Let f : M → M1 be a homomorphism of right a-modules and
00⟶⟶N′g′↓N1′uu1Ng↓N1vv1N′′g′′↓N1′′⟶⟶00
(E1)
a commutative diagram with exact rows of homomorphisms of left a-modules. The diagram of k-modules
TorA(M,N′′)TorA(f,g′′)↓TorA(M1,N1′′)∂(M,E)∂(M1,E1)TorA(M,N′)TorA(f,g′)↓TorA(M1,N1′)
is commutative.
This follows from X, p. 31, prop. 2, applied to the commutative diagram
00⟶⟶L(M)⊗AN′L(f)⊗g′↓L(M1)⊗AN1′1⊗u1⊗u1L(M)⊗ANL(f)⊗g↓L(M1)⊗AN11⊗v1⊗v1L(M)⊗AN′′L(f)⊗g′′↓L(M1)⊗AN1′′⟶⟶00.
In an analogous way, if N is a left a-module and
0→M′rMsM′′→0
an exact sequence of right a-modules, one defines linking homomorphisms
∂(F,N):TorA(M′′,N)→TorA(M′,N)
∂n(F,N):TornA(M′′,N)→Torn−1A(M′,N)
by ∂(F,N)=ψN(M′)−1∘∂(FN)∘ψN(M′′), where ∂(FN) is the linking homomorphism of the exact sequence
(FN)0⟶M′⊗AL(N)⟶M⊗AL(N)⟶M′′⊗AL(N)⟶0
deduced from F, and one has:
THEOREM 1 bis. — The left-unbounded sequence of homomorphisms of k-modules
⟶TornA(M′,N)TornA(r,1)TornA(M,N)TornA(s,1)TornA(M′′,N)∂n(F,N)Torn−1A(M′,N)
⋯⟶Tor1A(M′′,N)∂1(F,N)M′⊗ANr⊗1M⊗ANs⊗1M′′⊗AN⟶0
is exact.
We leave to the reader the task of stating and proving the properties analogous to the corollaries of th. 1 and to prop. 9. Moreover:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.
Nothing.