The connecting homomorphism H(B⊗AC′)→H(Z⊗AC′) associated with the exact sequence (12) is equal to H(i⊗1).
Indeed, let a∈H(B⊗AC′); since B is flat, a belongs to the image of B⊗AZ(C′), hence can be written as ∑λdaλ⊗bλ, where aλ∈C, bλ∈C′, and dbλ=0. The image of the class of a under the connecting homomorphism is, by definition, the class of D(∑aλ⊗bλ)=∑daλ⊗bλ=(i⊗1)(a), which proves the lemma.
The associated homology exact sequence to (12) is therefore
H(B⊗AC′)H(i⊗1)H(Z⊗AC′)H(j⊗1)H(C⊗AC′)
H(δ⊗1)H(B⊗AC′)(−1)H(i⊗1)H(Z⊗AC′)(−1).
On the other hand, since Z is flat, from (II) we obtain a sequence of graded k-modules
which is commutative by definition of the homomorphisms γ. But since the complexes B and Z are split and flat, γB and γZ are bijective (X, p. 65, Corollary 1). From this, on the one hand, we deduce that γC is injective and has image equal to KerH(δ⊗1), and on the other hand, that γB∘∂(II,H′) is injective with image equal to ImH(δ⊗1). The theorem follows immediately from this.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.