Bourbaki

Remark

Tag 0DXV, permanent. Cite it as [Bourbaki, Tag 0DXV].

Algebra, chapter X, § 6. Utilisation de résolutions non canoniques

The diagram of kk-modules

Tor⁡A(P,M)→ψ(S,R)H(S⊗AR)↓σP,M↓H(σ(S,R))Tor⁡A∘(M∘,P∘)→ψ(R∘,S∘)H(R∘⊗A∘S∘), \begin{array}{ccc} \operatorname{Tor}^A(P,M)&\xrightarrow{\psi(S,R)}&H(S\otimes_A R)\\ \downarrow{\sigma_{P,M}}&&\downarrow{H(\sigma(S,R))}\\ \operatorname{Tor}^{A^\circ}(M^\circ,P^\circ)&\xrightarrow{\psi(R^\circ,S^\circ)}&H(R^\circ\otimes_{A^\circ}S^\circ), \end{array}

where σP,M\sigma_{P,M} and σ(S,R)\sigma(S,R) are the commutation isomorphisms (X, p. 71 and 63), is commutative: it is obtained in fact, by passing to homology, from the commutative diagram of complexes

L(P)⊗AL(M)→β⊗αS⊗AR↓σ(L(P),L(M))↓σ(S,R)L(M∘)⊗A∘L(P∘)→α⊗βR∘⊗A∘S∘ \begin{array}{ccc} L(P)\otimes_A L(M)&\xrightarrow{\beta\otimes\alpha}&S\otimes_A R\\ \downarrow{\sigma(L(P),L(M))}&&\downarrow{\sigma(S,R)}\\ L(M^\circ)\otimes_{A^\circ}L(P^\circ)&\xrightarrow{\alpha\otimes\beta}&R^\circ\otimes_{A^\circ}S^\circ \end{array}

("the morphisms ψ\psi are compatible with the commutation isomorphisms").

Analogously, let a1:R1→Ma_1:R_1\to M, b1:S1→Pb_1:S_1\to P, c1:N→E1c_1:N\to E_1 be morphisms of complexes, where R1R_1 and S1S_1 are projective and right zero and E1E_1 injective and left zero. By X, p. 49, prop. 3 and 3 bis, there exist morphisms of complexes

α1:R1→L(M),β1:S1→L(P),γ1:I(N)→E1 \alpha_1:R_1\to L(M),\qquad \beta_1:S_1\to L(P),\qquad \gamma_1:I(N)\to E_1

such that pM∘α1=a1,pP∘β1=b1,γ1∘eN=c1p_M \circ \alpha_1 = a_1, p_P \circ \beta_1 = b_1, \gamma_1 \circ e_N = c_1, whence morphisms of complexes

β1⊗α1:S1⊗AR1→L(P)⊗AL(M), \beta_1 \otimes \alpha_1 : S_1 \otimes_A R_1 \to L(P) \otimes_A L(M),
Homgr⁡A(α1,γ1):Homgr⁡A(L(M),l(N))→Homgr⁡A(R1,E1), \operatorname{Homgr}_A (\alpha_1, \gamma_1) : \operatorname{Homgr}_A (L(M), l(N)) \to \operatorname{Homgr}_A (R_1, E_1),

and by passing to homology, graded k-linear mappings of degree 0:

ψ′(S1,R1):H(S1⊗AR1)→Tor⁡A(P,M) \psi'(S_1, R_1) : H(S_1 \otimes_A R_1) \to \operatorname{Tor}^A (P, M)
φ′(R1,E1):Ext⁡A(M,N)→H(Homgr⁡A(R1,E1)) \varphi'(R_1, E_1) : \operatorname{Ext}_A (M, N) \to H(\operatorname{Homgr}_A (R_1, E_1))

which one verifies, as above, to be independent of the choice of α1,β1,γ1\alpha_1, \beta_1, \gamma_1.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Translated with machine help, not yet reviewed by a person.