Bourbaki

Proposition 1

Tag 0DXW, permanent. Cite it as [Bourbaki, Tag 0DXW].

Algebra, chapter X, § 6. Utilisation de résolutions non canoniques

If a1,b1,c1a_1, b_1, c_1 are homologisms, ψ′(S1,R1)\psi'(S_1, R_1) and φ′(R1,E1)\varphi'(R_1, E_1) are the reciprocal bijections of the bijections ψ(S1,R1)\psi(S_1, R_1) and φ(R1,E1)\varphi(R_1, E_1) respectively.

In fact, f=(β⊗α)∘(β1⊗α1)f = (\beta \otimes \alpha) \circ (\beta_1 \otimes \alpha_1) is a morphism of the complex S1⊗AR1S_1 \otimes_A R_1 into itself, and one has (h1∘α1)∘f=f(h_1 \circ \alpha_1) \circ f = f. By X, p. 49, prop. 3 and 3 bis, ff is a homotopism, hence H(f)=1H(f) = 1 and

ψ(S1,R1)∘ψ′(B1,R1)=H(β⊗α)∘H(β1⊗α1)=H(f)=1; \psi(S_1, R_1) \circ \psi'(B_1, R_1) = H(\beta \otimes \alpha) \circ H(\beta_1 \otimes \alpha_1) = H(f) = 1;

analogously ψ′(S1,R1)∘ψ(S1,R1)=1\psi'(S_1, R_1) \circ \psi(S_1, R_1) = 1. One reasons in an analogous manner for the mappings φ\varphi and φ′\varphi'.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Translated with machine help, not yet reviewed by a person.