Bourbaki

Definition 1

Tag 0DYG, permanent. Cite it as [Bourbaki, Tag 0DYG].

Algebra, chapter X, § 6. Utilisation de résolutions non canoniques

Let M be a left Z(G)\mathbf{Z}^{(G)}-module (resp. right), n an integer ⩾0\geqslant 0. The group ExtZ(G)n(Z,M)\mathrm{Ext}_{\mathbf{Z}^{(G)}}^n(\mathbf{Z}, M) (resp. TornZ(G)(M,Z)\mathrm{Tor}_n^{\mathbf{Z}^{(G)}}(M, \mathbf{Z})) is denoted by Hn(G,M)H^n(G, M) (resp. Hn(G,M)H_n(G, M)) and is called the nth cohomology group (resp. homology group) of G with coefficients in M.

The standard resolution (X, p. 58) B(Z(G),Z)B(\mathbf{Z}^{(G)}, \mathbf{Z}) is a free resolution of the Z(G)\mathbf{Z}^{(G)}-module Z\mathbf{Z}; it follows that the groups Hn(G,M)H^n(G, M) (resp. Hn(G,M)H_n(G, M)) identify with the homology groups of the complex:

HomZ(G)(B(Z(G),Z),M)(resp. M⊗Z(G)B(Z(G),Z)). \mathrm{Hom}_{\mathbf{Z}^{(G)}}(B(\mathbf{Z}^{(G)}, \mathbf{Z}), M) \quad (\text{resp. } M \otimes_{\mathbf{Z}^{(G)}} B(\mathbf{Z}^{(G)}, \mathbf{Z})) .

Using the canonical isomorphism of (Z(G))⊗n(\mathbf{Z}^{(G)})^{\otimes n} onto Z(Gn)\mathbf{Z}^{(G^n)} (III, p. 36) and the properties of extension of scalars (II, p. 82), one concludes that Hn(G,M)H^n(G, M) is canonically isomorphic to the homology group of ascending degree nn of the complex C(G,M)C(G, M) defined as follows: Cn(G,M)=0C^n(G, M) = 0 for n<0n < 0; for n⩾0n \geqslant 0, Cn(G,M)C^n(G, M) is the Z\mathbf{Z}-module of mappings of GnG^n into M; for n⩾0n \geqslant 0, the differential dn:Cn(G,M)→Cn+1(G,M)d^n : C^n(G, M) \to C^{n+1}(G, M) is given by

(dnf)(g0,...,gn)=g0⋅f(g1,...,gn)+∑i=0n−1(−1)i+1f(g0,...,gigi+1,...,gn) (d^n f)(g_0, ..., g_n) = g_0 \cdot f(g_1, ..., g_n) + \sum_{i=0}^{n-1} (-1)^{i+1} f(g_0, ..., g_i g_{i+1}, ..., g_n)
+(−1)n+1f(g0,...,gn−1) + (-1)^{n+1} f(g_0, ..., g_{n-1})

for any ff in Cn(G,M)C^n(G, M) and g0,...,gng_0, ..., g_n in G.

Analogously, Hn(G,M)H_n(G, M) identifies with the homology group of degree nn of the complex C′(G,M)C'(G, M), where Cn′(G,M)=M⊗ZZ(Gn)C'_n(G, M) = M \otimes_{\mathbf{Z}} \mathbf{Z}^{(G^n)} for n⩾0n \geqslant 0, Cn′(G,M)=0C'_n(G, M) = 0 for n<0n < 0, the differential dn:Cn′(G,M)→Cn−1′(G,M)d_n : C'_n(G, M) \to C'_{n-1}(G, M) being defined by:

dn(m⊗eg1,...,gn)=m⋅g1⊗eg2,...,gn+∑i=1n−1(−1)im⊗eg1,...,gigi+1,...,gn d_n(m \otimes e_{g_1, ..., g_n}) = m \cdot g_1 \otimes e_{g_2, ..., g_n} + \sum_{i=1}^{n-1} (-1)^i m \otimes e_{g_1, ..., g_i g_{i+1}, ..., g_n}
+(−1)nm⊗eg1,...,gn−1 + (-1)^n m \otimes e_{g_1, ..., g_{n-1}}

for any n⩾1n \geqslant 1, mm in M and g1,...,gng_1, ..., g_n in G.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Translated with machine help, not yet reviewed by a person.