Let M be a left Z(G)-module (resp. right), n an integer ⩾0. The group ExtZ(G)n(Z,M) (resp. TornZ(G)(M,Z)) is denoted by Hn(G,M) (resp. Hn(G,M)) and is called the nth cohomology group (resp. homology group) of G with coefficients in M.
The standard resolution (X, p. 58) B(Z(G),Z) is a free resolution of the Z(G)-module Z; it follows that the groups Hn(G,M) (resp. Hn(G,M)) identify with the homology groups of the complex:
HomZ(G)(B(Z(G),Z),M)(resp. M⊗Z(G)B(Z(G),Z)).
Using the canonical isomorphism of (Z(G))⊗n onto Z(Gn) (III, p. 36) and the properties of extension of scalars (II, p. 82), one concludes that Hn(G,M) is canonically isomorphic to the homology group of ascending degree n of the complex C(G,M) defined as follows: Cn(G,M)=0 for n<0; for n⩾0, Cn(G,M) is the Z-module of mappings of Gn into M; for n⩾0, the differential dn:Cn(G,M)→Cn+1(G,M) is given by
(dnf)(g0,...,gn)=g0⋅f(g1,...,gn)+i=0∑n−1(−1)i+1f(g0,...,gigi+1,...,gn)
+(−1)n+1f(g0,...,gn−1)
for any f in Cn(G,M) and g0,...,gn in G.
Analogously, Hn(G,M) identifies with the homology group of degree n of the complex C′(G,M), where Cn′(G,M)=M⊗ZZ(Gn) for n⩾0, Cn′(G,M)=0 for n<0, the differential dn:Cn′(G,M)→Cn−1′(G,M) being defined by:
dn(m⊗eg1,...,gn)=m⋅g1⊗eg2,...,gn+i=1∑n−1(−1)im⊗eg1,...,gigi+1,...,gn
+(−1)nm⊗eg1,...,gn−1
for any n⩾1, m in M and g1,...,gn in G.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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