Bourbaki

Example 3

Tag 0DYJ, permanent. Cite it as [Bourbaki, Tag 0DYJ].

Algebra, chapter X, § 6. Utilisation de résolutions non canoniques

Analogously H2(G,M)H^2(G,M) is isomorphic to the Z\mathbf{Z}-module Z2(G,M)/B2(G,M)Z^2(G,M)/B^2(G,M), where Z2(G,M)Z^2(G,M) is the Z\mathbf{Z}-module of mappings ff of G×GG\times G into MM, satisfying:

g1.f(g2,g3)−f(g1g2,g3)+f(g1,g2g3)−f(g1,g2)=0 g_1.f(g_2,g_3)-f(g_1g_2,g_3)+f(g_1,g_2g_3)-f(g_1,g_2)=0

whatever g1,g2,g3g_1,g_2,g_3 in GG may be, and B2(G,M)B^2(G,M) is the sub-Z\mathbf{Z}-module of Z2(G,M)Z^2(G,M) consisting of the ff for which there exists a mapping hh of GG into MM such that:

f(g1,g2)=g1.h(g2)−h(g1g2)+h(g1) f(g_1,g_2)=g_1.h(g_2)-h(g_1g_2)+h(g_1)

whatever g1,g2g_1,g_2 in GG may be.

Thus one recovers the definition of the group H2(G,M)H^2(G,M) given in VIII, App. II; in particular there exists a canonical isomorphism of H2(G,M)H^2(G,M) onto the group of extension classes of GG by MM (loc. cit.).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Translated with machine help, not yet reviewed by a person.