If u∈HomA(N,P), v∈ExtA(M,N), then
u∘v=ExtA(lM,u)(v)∈ExtA(M,P):
analogously, if u∈ExtA(N,P), v∈HomA(M,N), then
u∘v=ExtA(v,lP)(u)∈ExtA(M,P).
This follows from the definitions and the remarks of X. p. 88.
If Q,M,N,P are four left A-modules, and if
u∈ExtA(N,P),v∈ExtA(M,N),w∈ExtA(Q,M),
then (u∘v)∘w=u∘(v∘w): the composition product is associative; we will therefore denote the composition of several elements without parentheses. In particular, by Example 2:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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