Bourbaki

Example 3

Tag 0DZI, permanent. Cite it as [Bourbaki, Tag 0DZI].

Algebra, chapter X, § 7. Produit de composition

Let M,N,M′,N′M, N, M', N' be four left AA-modules. If u∈ExtA(M,N)u \in \mathrm{Ext}_A(M, N), f∈HomA(M′,M)f \in \mathrm{Hom}_A(M', M), g∈HomA(N,N′)g \in \mathrm{Hom}_A(N, N'), then

(3)

ExtA(f,g)(u)=g∘u∘f∈ExtA(M′,N′). \mathrm{Ext}_A(f, g)(u) = g \circ u \circ f \in \mathrm{Ext}_A(M', N').

This provides a new proof of the kk-bilinearity of the mapping (f,g)→ExtA(f,g)(f, g) \to \mathrm{Ext}_A(f, g) (X, p. 88, Prop. 6).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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