Let
(6)
0 → P → S m → S m − 1 → … → S 1 → λ N → 0
0 \to P \to S_m \to S_{m-1} \to \ldots \to S_1 \xrightarrow{\lambda} N \to 0
0 → P → S m → S m − 1 → … → S 1 λ N → 0 (7)
0 → N ↠ R n → R n − 1 → … → R 1 → M → 0
0 \to N \twoheadrightarrow R_n \to R_{n-1} \to \ldots \to R_1 \to M \to 0
0 → N ↠ R n → R n − 1 → … → R 1 → M → 0 be two exact sequences of left A-modules with respective classes θ ∈ Ext^m_A(N, P) and θ' ∈ Ext^n_A(M, N). The class in Ext^{m+n}_A(M, P) associated with the exact sequence (8)
0 → P → S m → … → S 1 → μ ∘ λ R n → … → R 1 → M → 0
0 \to P \to S_m \to \ldots \to S_1 \xrightarrow{\mu \circ \lambda} R_n \to \ldots \to R_1 \to M \to 0
0 → P → S m → … → S 1 μ ∘ λ R n → … → R 1 → M → 0 is the composition product θ ∘ θ'.
Choose commutative diagrams
0 ⟶ P ⟶ I 0 ( P ) ⟶ … ⟶ I m − 1 ( P ) → δ P m − 1 I m ( P ) l P ↑ w 0 ↑ w m − 1 ↑ w m ↑ 0 ⟶ P ⟶ S m ⟶ … ⟶ S 1 → λ N ⟶ 0 ,
\begin{array}{cccccccccccc}
0 & \longrightarrow & P & \longrightarrow & I^0(P) & \longrightarrow & \ldots \longrightarrow & I^{m-1}(P) & \xrightarrow{\delta_P^{m-1}} & I^m(P) \\
& & ^{l_P}\uparrow & & ^{w^0}\uparrow & & & ^{w^{m-1}}\uparrow & & ^{w^m}\uparrow \\
0 & \longrightarrow & P & \longrightarrow & S_m & \longrightarrow & \ldots \longrightarrow & S_1 & \xrightarrow{\lambda} & N & \longrightarrow & 0 ,
\end{array}
0 0 ⟶ ⟶ P l P ↑ P ⟶ ⟶ I 0 ( P ) w 0 ↑ S m ⟶ ⟶ … ⟶ … ⟶ I m − 1 ( P ) w m − 1 ↑ S 1 δ P m − 1 λ I m ( P ) w m ↑ N ⟶ 0 ,
0 ⟶ N → e N I 0 ( N ) ⟶ … ⟶ I n − 1 ( N ) ⟶ I n ( N ) 1 N ↑ v 0 ↑ v n − 1 ↑ v n ↑ 0 ⟶ N → μ R n ⟶ … ⟶ R 1 ⟶ M ⟶ 0.
\begin{array}{cccccccccccc}
0 & \longrightarrow & N & \xrightarrow{e_N} & I^0(N) & \longrightarrow & \ldots \longrightarrow & I^{n-1}(N) & \longrightarrow & I^n(N) \\
& & ^{1_N}\uparrow & & ^{v^0}\uparrow & & & ^{v^{n-1}}\uparrow & & ^{v^n}\uparrow \\
0 & \longrightarrow & N & \xrightarrow{\mu} & R_n & \longrightarrow & \ldots \longrightarrow & R_1 & \longrightarrow & M & \longrightarrow & 0 .
\end{array}
0 0 ⟶ ⟶ N 1 N ↑ N e N μ I 0 ( N ) v 0 ↑ R n ⟶ ⟶ … ⟶ … ⟶ I n − 1 ( N ) v n − 1 ↑ R 1 ⟶ ⟶ I n ( N ) v n ↑ M ⟶ 0.
Since I m ( P ) I^m(P) I m ( P ) is injective, there exists a homomorphism h 0 : I 0 ( N ) → I m ( P ) h^0 \colon I^0(N) \rightarrow I^m(P) h 0 : I 0 ( N ) → I m ( P ) such that w m = h 0 ∘ e N w^m = h^0 \circ e_N w m = h 0 ∘ e N ; according to X, p. 49, Proposition 3 bis, h 0 h^0 h 0 extends to a morphism of complexes h : I ( N ) → I ( P ) ( − m ) h \colon I(N) \rightarrow I(P)\, (-m) h : I ( N ) → I ( P ) ( − m ) . Thus w m = h 0 ∘ e N = h 0 ∘ v 0 ∘ μ w^m = h^0 \circ e_N = h^0 \circ v^0 \circ \mu w m = h 0 ∘ e N = h 0 ∘ v 0 ∘ μ , hence
δ I m − 1 ∘ w m − 1 = w m ∘ λ = h 0 ∘ v 0 ∘ ( μ ∘ λ ) ,
\delta_I^{m-1} \circ w^{m-1} = w^m \circ \lambda = h^0 \circ v^0 \circ (\mu \circ \lambda),
δ I m − 1 ∘ w m − 1 = w m ∘ λ = h 0 ∘ v 0 ∘ ( μ ∘ λ ) ,
and the following diagram is commutative:
0 ⟶ P ⟶ I 0 ( P ) ⟶ ⋯ ⟶ I m − 1 ( P ) ⟶ I m ( P ) ⟶ I m + 1 ( P ) ⟶ ⋯ ⟶ I m + n ( P ) ↑ i P ↑ w 0 ↑ w m − 1 ↑ t 0 ↑ t 1 ↑ t n 0 ⟶ P ⟶ S m ⟶ ⋯ ⟶ S 1 → μ ∘ λ R n ⟶ R n − 1 ⟶ ⋯ ⟶ M ⟶ 0
\begin{array}{ccccccccccccccccccc}
0&\longrightarrow&P&\longrightarrow&I^0(P)&\longrightarrow&\cdots&\longrightarrow&I^{m-1}(P)&\longrightarrow&I^m(P)&\longrightarrow&I^{m+1}(P)&\longrightarrow&\cdots&\longrightarrow&I^{m+n}(P)\\
&&\uparrow^{i_P}&&\uparrow^{w^0}&&&&\uparrow^{w^{m-1}}&&\uparrow^{t^0}&&\uparrow^{t^1}&&&&\uparrow^{t^n}\\
0&\longrightarrow&P&\longrightarrow&S_m&\longrightarrow&\cdots&\longrightarrow&S_1&\xrightarrow[\mu\circ\lambda]{}&R_n&\longrightarrow&R_{n-1}&\longrightarrow&\cdots&\longrightarrow&M&\longrightarrow&0
\end{array}
0 0 ⟶ ⟶ P ↑ i P P ⟶ ⟶ I 0 ( P ) ↑ w 0 S m ⟶ ⟶ ⋯ ⋯ ⟶ ⟶ I m − 1 ( P ) ↑ w m − 1 S 1 ⟶ μ ∘ λ I m ( P ) ↑ t 0 R n ⟶ ⟶ I m + 1 ( P ) ↑ t 1 R n − 1 ⟶ ⟶ ⋯ ⋯ ⟶ ⟶ I m + n ( P ) ↑ t n M ⟶ 0
where t 0 = h 0 ∘ v 0 t^0=h^0\circ v^0 t 0 = h 0 ∘ v 0 , t 1 = ( − 1 ) m h 1 ∘ v 1 t^1=(-1)^m h^1\circ v^1 t 1 = ( − 1 ) m h 1 ∘ v 1 , … \ldots … , t i = ( − 1 ) m i h i ∘ v i t^i=(-1)^{mi}h^i\circ v^i t i = ( − 1 ) mi h i ∘ v i , … \ldots … , t n = ( − 1 ) m n h n ∘ v n t^n=(-1)^{mn}h^n\circ v^n t n = ( − 1 ) mn h n ∘ v n .
The class θ \theta θ associated to (6) is that of ( − 1 ) m ( m + 1 ) / 2 w m ∈ Homgr A m ( N , I ( P ) ) (-1)^{m(m+1)/2}w^m\in\operatorname{Homgr}_A^m(N,I(P)) ( − 1 ) m ( m + 1 ) /2 w m ∈ Homgr A m ( N , I ( P )) , corresponding by the isomorphism α N , P \alpha_{N,P} α N , P to the class of ( − 1 ) m ( m + 1 ) / 2 h ∈ Homgr A m ( I ( N ) , I ( P ) ) (-1)^{m(m+1)/2}h\in\operatorname{Homgr}_A^m(I(N),I(P)) ( − 1 ) m ( m + 1 ) /2 h ∈ Homgr A m ( I ( N ) , I ( P )) ; the class θ ′ \theta' θ ′ associated to (7) is that of ( − 1 ) n ( n + 1 ) / 2 v n ∈ Homgr n ( M , I ( N ) ) (-1)^{n(n+1)/2}v^n\in\operatorname{Homgr}^n(M,I(N)) ( − 1 ) n ( n + 1 ) /2 v n ∈ Homgr n ( M , I ( N )) , the class associated to (8) is that of ( − 1 ) ( m + n ) ( m + n + 1 ) / 2 t n ∈ Homgr m + n ( M , I ( P ) ) (-1)^{(m+n)(m+n+1)/2}t^n\in\operatorname{Homgr}^{m+n}(M,I(P)) ( − 1 ) ( m + n ) ( m + n + 1 ) /2 t n ∈ Homgr m + n ( M , I ( P )) , hence the conclusion, according to the definition of the composition product (X, p. 114) and the formula
m ( m + 1 ) / 2 + n ( n + 1 ) / 2 = ( m + n ) ( m + n + 1 ) / 2 − m n .
m(m+1)/2+n(n+1)/2=(m+n)(m+n+1)/2-mn.
m ( m + 1 ) /2 + n ( n + 1 ) /2 = ( m + n ) ( m + n + 1 ) /2 − mn .
4. — Considérons un diagramme commutatif de A A A -modules à lignes exactes
0 ⟶ N ⟶ R n ⟶ R n − 1 ⟶ ⋯ ⟶ R 1 ⟶ M ⟶ 0 ↓ g ↓ ↓ ↓ ↓ f 0 ⟶ N ′ ⟶ R n ′ ⟶ R n − 1 ′ ⟶ ⋯ ⟶ R 1 ′ ⟶ M ′ ⟶ 0.
\begin{array}{ccccccccccccccc}
0&\longrightarrow&N&\longrightarrow&R_n&\longrightarrow&R_{n-1}&\longrightarrow&\cdots&\longrightarrow&R_1&\longrightarrow&M&\longrightarrow&0\\
&&\downarrow^{g}&&\downarrow&&\downarrow&&&&\downarrow&&\downarrow^{f}&&\\
0&\longrightarrow&N'&\longrightarrow&R'_n&\longrightarrow&R'_{n-1}&\longrightarrow&\cdots&\longrightarrow&R'_1&\longrightarrow&M'&\longrightarrow&0.
\end{array}
0 0 ⟶ ⟶ N ↓ g N ′ ⟶ ⟶ R n ↓ R n ′ ⟶ ⟶ R n − 1 ↓ R n − 1 ′ ⟶ ⟶ ⋯ ⋯ ⟶ ⟶ R 1 ↓ R 1 ′ ⟶ ⟶ M ↓ f M ′ ⟶ ⟶ 0 0.
Let θ \theta θ (resp. θ ′ \theta' θ ′ ) be the class of the first (resp. second) row in
Ext A n ( M , N ) (resp. Ext A n ( M ′ , N ′ ) ) .
\operatorname{Ext}_A^n(M,N)\quad\text{(resp. }\operatorname{Ext}_A^n(M',N')\text{)}.
Ext A n ( M , N ) (resp. Ext A n ( M ′ , N ′ ) ) .
In Ext A n ( M , N ′ ) \operatorname{Ext}_A^n(M,N') Ext A n ( M , N ′ ) , we have θ ′ ∘ f = g ∘ θ \theta'\circ f=g\circ\theta θ ′ ∘ f = g ∘ θ .
Indeed, consider a commutative diagram
L n ( M ) → d n L n − 1 ( M ) ⟶ ⋯ ⟶ L 0 ( M ) → p M M ⟶ 0 ↓ u n ↓ ↓ ↓ 1 0 ⟶ N ⟶ R n ⟶ ⋯ ⟶ R 1 ⟶ M ⟶ 0 ↓ g ↓ ↓ ↓ f 0 ⟶ N ′ ⟶ R n ′ ⟶ ⋯ ⟶ R 1 ′ ⟶ M ′ ⟶ 0 ↓ ↓ ↓ ↓ v n 0 ⟶ N ′ → ϵ N ′ I 0 ( N ′ ) → δ 0 ⋯ ⟶ I n − 1 ( N ′ ) → δ n − 1 I n ( N ′ )
\begin{array}{ccccccccccccc}
L_n(M)&\xrightarrow{d_n}&L_{n-1}(M)&\longrightarrow&\cdots&\longrightarrow&L_0(M)&\xrightarrow{p_M}&M&\longrightarrow&0\\
\downarrow^{u_n}&&\downarrow&&&&\downarrow&&\downarrow^{1}\\
0&\longrightarrow&N&\longrightarrow&R_n&\longrightarrow&\cdots&\longrightarrow&R_1&\longrightarrow&M&\longrightarrow&0\\
&&\downarrow^{g}&&\downarrow&&&&\downarrow&&\downarrow^{f}\\
0&\longrightarrow&N'&\longrightarrow&R'_n&\longrightarrow&\cdots&\longrightarrow&R'_1&\longrightarrow&M'&\longrightarrow&0\\
&&\downarrow&&\downarrow&&&&\downarrow&&\downarrow^{v^n}\\
0&\longrightarrow&N'&\xrightarrow{\epsilon_{N'}}&I^0(N')&\xrightarrow{\delta^0}&\cdots&\longrightarrow&I^{n-1}(N')&\xrightarrow{\delta^{n-1}}&I^n(N')
\end{array}
L n ( M ) ↓ u n 0 0 0 d n ⟶ ⟶ ⟶ L n − 1 ( M ) ↓ N ↓ g N ′ ↓ N ′ ⟶ ⟶ ⟶ ϵ N ′ ⋯ R n ↓ R n ′ ↓ I 0 ( N ′ ) ⟶ ⟶ ⟶ δ 0 L 0 ( M ) ↓ ⋯ ⋯ ⋯ p M ⟶ ⟶ ⟶ M ↓ 1 R 1 ↓ R 1 ′ ↓ I n − 1 ( N ′ ) ⟶ ⟶ ⟶ δ n − 1 0 M ↓ f M ′ ↓ v n I n ( N ′ ) ⟶ ⟶ 0 0
By definition, θ ′ ∘ f \theta'\circ f θ ′ ∘ f is the class of ( − 1 ) n ( n + 1 ) / 2 v n ∘ f ∘ p M ∈ Homgr n ( L ( M ) , I ( N ′ ) ) (-1)^{n(n+1)/2}v^n\circ f\circ p_M\in\operatorname{Homgr}^n(L(M),I(N')) ( − 1 ) n ( n + 1 ) /2 v n ∘ f ∘ p M ∈ Homgr n ( L ( M ) , I ( N ′ )) , while g ∘ θ g\circ\theta g ∘ θ is the class of ( − 1 ) n ( n + 1 ) / 2 ϵ N ′ ∘ g ∘ u n (-1)^{n(n+1)/2}\epsilon_{N'}\circ g\circ u_n ( − 1 ) n ( n + 1 ) /2 ϵ N ′ ∘ g ∘ u n . According to Lemma 1, applied to the two extreme lines of the diagram, these two classes are equal.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.
Nothing.