Bourbaki

Corollary 4

Tag 0E01, permanent. Cite it as [Bourbaki, Tag 0E01].

Algebra, chapter X, § 7. Produit de composition

If each module Ri, i=1,...,n,R_i,\ i = 1, ..., n, is injective (resp. projective), the mapping α↦θ∘α\alpha \mapsto \theta \circ \alpha (resp. α↦α∘θ\alpha \mapsto \alpha \circ \theta) from ExtAm(P,M)\mathrm{Ext}_A^m(P, M) to ExtAm+n(P,N)\mathrm{Ext}_A^{m+n}(P, N) (resp. from ExtAm(N,P)\mathrm{Ext}_A^m(N, P) to ExtAm+n(M,P)\mathrm{Ext}_A^{m+n}(M, P)) is bijective for every AA-module PP and every integer m>0m > 0.

This indeed follows from Corollary 3 and the exact sequences

ExtAm+i−1(P,Ri)→ExtAm+i−1(P,Ki−1)→ExtAm+i(P,Ki)→ExtAm+i(P,Ri) \mathrm{Ext}_A^{m+i-1}(P, R_i) \to \mathrm{Ext}_A^{m+i-1}(P, K_{i-1}) \to \mathrm{Ext}_A^{m+i}(P, K_i) \to \mathrm{Ext}_A^{m+i}(P, R_i)
(resp. ExtAm+i−1(Ri,P)→ExtAm+i−1(Ki,P)→ExtAm+i(Ki−1,P)→ExtAm+i(Ri,P)\mathrm{Ext}_A^{m+i-1}(R_i, P) \to \mathrm{Ext}_A^{m+i-1}(K_i, P) \to \mathrm{Ext}_A^{m+i}(K_{i-1}, P) \to \mathrm{Ext}_A^{m+i}(R_i, P)), whose extreme terms are zero by assumption.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Translated with machine help, not yet reviewed by a person.