Bourbaki

Remark 1

Tag 0E03, permanent. Cite it as [Bourbaki, Tag 0E03].

Algebra, chapter X, § 7. Produit de composition

If one uses the isomorphisms ψ\psi of X, p. 69, one can also define the composition product by the commutative diagram

ExtAn(P,Q)×TormA(P,M)→cP,Q;MTorm−nA(Q,M)aˉP,Q×ψP(M)↓↓ψQ(M)Hn(HomgrA(L(P),L(Q)))×Hm(L(P)⊗AM)⟶Hm−n(L(Q)⊗AM); \begin{array}{ccc} \mathrm{Ext}_A^n(P, Q) \times \mathrm{Tor}_m^A(P, M) & \xrightarrow{c_{P,Q;M}} & \mathrm{Tor}_{m-n}^A(Q, M) \\ \bar{a}_{P,Q} \times \psi_{P(M)} \downarrow & & \downarrow \psi_{Q(M)} \\ H^n(\mathrm{Homgr}_A(L(P), L(Q))) \times H_m(L(P) \otimes_A M) & \longrightarrow & H_{m-n}(L(Q) \otimes_A M); \end{array}

in other words, one represents α\alpha by a morphism ff from L(P)L(P) to L(Q)(−n)L(Q) (-n), γ\gamma by a cycle x∈Lm(P)⊗AMx \in L_m(P) \otimes_A M, and α∘γ\alpha \circ \gamma is the class of the cycle

(fm⊗1M)(x)∈Lm−n(Q)⊗AM. (f_m \otimes 1_M)(x) \in L_{m-n}(Q) \otimes_A M.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Translated with machine help, not yet reviewed by a person.